1、課題2 浙教版 七年級(jí)下第3章 整式的乘除3.7整式的除法BA12345BA678D答 案 呈 現(xiàn)溫馨提示：點(diǎn)擊 進(jìn)入講評(píng)習(xí)題鏈接9A1011121314DC3xy151617【金華期中】計(jì)算：(6a3b4)(3a2b)()A2 B2ab3C3ab3 D2a5b5B1【嘉興期末】計(jì)算：(12x38x216x)(4x)的結(jié)果是()A3x22x4 B3x22x4C3x22x4 D3x22x4A2xmynx2y3xy，則有()Am2，n6 Bm3，n4Cm2，n3 Dm3，n5B3下列計(jì)算正確的是()A(6xy5x)x6y5B(15x2y10 xy2)(5xy)3x2y2C(5x32x2x)x5x2

2、2xD(12x3y8x3)(4x)23xy2A4已知多項(xiàng)式(17x23x4)(ax2bxc)能被5x整除，且商為2x1，則abc()A12 B13 C14 D19D5計(jì)算(81xn56xn33xn2)(3xn1)等于()A27x62x4x3 B27x62x4xC27x62x4x3 D27x42x2x6A已知a1.6109，b4103，則a2b等于()A4107 B81014C6.4105 D6.41014D78C【杭州期中】計(jì)算：(6x2y2xy2)(2xy)_.93xy【點(diǎn)撥】根據(jù)多項(xiàng)式除以單項(xiàng)式的法則計(jì)算(6x2y2xy2)(2xy)6x2y(2xy)2xy2(2xy)3xy.103m2n

3、27m2nt2n【寧波期末】計(jì)算：(1)(3a2b)3(2ab4)2(6a5b3)；11解：原式27a6b34a2b8(6a5b3)108a8b11(6a5b3)18a3b8.(2)(2ab)(ab)(8a3b4a2b2)4ab.解：原式2a22ababb2(8a3b4ab4a2b24ab)2a2abb2(2a2ab)2a2abb22a2abb2.化簡(jiǎn)：(1)(3xy)(3xy)(9x3y6xy3)3xy；12解：原式9x2y2(3x22y2)9x2y23x22y26x2y2.計(jì)算：(1)(2x)33x(x2x2)；(2)(x2y)2(x2y)(x2y)(4y)；13解：原式8x33x26x32x33x2.原式x24xy4y2(x24y2)(4y)(4xy8y2)(4y)x2y.(3)(xy)2y(2xy)8x(2x)已知2ab5，求a2b22b(ab)(ab)2 (4b)的值14莜莜不小心將墨水滴到了課本上，剛好把數(shù)學(xué)題(9x5y22x3y)xy的運(yùn)算符號(hào)遮住了(1)若被墨水遮住的運(yùn)算符號(hào)為乘號(hào)，求該數(shù)學(xué)題的計(jì)算結(jié)果；15解：(9x5y22x3y)xy9x6y32x4y2.(2)若該數(shù)學(xué)題的結(jié)果為9x4y2x2，求被墨水遮住的運(yùn)算符號(hào)解：(9x5y22x3y)xy9x4y2x2，被墨水遮住的運(yùn)算符號(hào)為.16小亮也舉起了手，說小明的解題過程不對(duì)，并指了出來老師肯定