1、.肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿

2、薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀

3、螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄

4、蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞

5、蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆

6、螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀

7、蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁

8、蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅

9、螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆

10、蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇

11、蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁

12、螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節

13、蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆

14、蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇

15、螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈

16、薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆薁袃羄莂薀肅腿莈蕿螅肂芄薈袇羋膀薇罿肀葿薇蠆芆蒞蚆螁聿芁蚅襖芄膇蚄羆肇蒆蚃螆袀蒂

17、螞袈膅莈蟻羀羈芄蟻蝕膄膀蝕螂羆蒈蝿裊膂莄螈羇羅芀螇蚇膀膆螆衿羃薅螅羈羋蒁螅肅肁莇螄螃芇芃莀裊肀腿荿羈芅蕆蒈蚇肈莃蒈螀芃艿蕆羂肆芅蒆肄罿薄蒅螄膄蒀蒄袆羇莆蒃罿膃節蒃蚈羆膈薂螁膁蒆 GMAT數學高分攻略I GMAT數學50分+的標準： 1. 拿到一道數學題，能夠在10-30秒 讀懂題目后：能夠迅速識別這道題它想考我什么（知識點方向）、馬虎的陷阱在哪里（馬虎是字面的，可以一眼識別）3. 思維層次：1和2做好后，思路的方向就基本出來了，包括這道題需要“試算”、“特值反例”、直接代公式、集合的venn或二維表、etc，也會知道應該這么去想和應該避免的思路歧義，這步就自然會出現對“思維陷阱”的敏感。整個過

18、程：渾然天成！II II. 學生容易犯的GMAT數學錯誤類型： 1 理解問題: 致命卻容易被思維好邏輯強的同學忽略！【表現】：1） 完全無法讀懂字面意思2） 能讀懂字面意思，但是無法在規定時間能在規定時間 知識點遺忘【表現】：能讀懂題，且有思路的大致方向，但對于完成該思路的工具（如描述統計的公式、集合的2種類型的處理方式，排列組合和概率的公式，etc）完全沒有印象或雖然有印象但是不能系統駕馭，導致最終不能完成題目。3 思維陷阱【表現】：能夠讀懂題目且知道思路以及運用的工具，但是由于加入了自己的主觀或過去的常識導致自己加了條件，在這樣的情況下解題，出現偏差。Eg：（DS）x是否能被z整除？分析：

19、此題很多同學在看2個選項時首先會去想z是否是x的因子，而忽略了本題的前提“x和z必須同時為整數”，而這一點是在判斷“是否充分”時不可忽略的。這樣的錯誤源于自己加入了條件“x和z是整數”，或根本不知道“整除”是針對整數而言的（后者這個屬于第二類錯誤）！4 馬虎問題【表現】：計算錯誤，把三角形的“height”看成“side”，etc 5 解題過程不必要的繁復，浪費時間：該類問題常見于DS題【根源】：沒有搞清楚DS“充分性”的含義！主要有以下兩大類（其他占比很小的零碎題型就不總結了）(1) what 型：只有能夠求出唯一值來回答what才叫充分！Eg:What is the value of th

20、e integer n ?(1)(2) Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.BOTH statements TOGETHER are sufficient, but NEITHER statementALONE is sufficient. EACH statement ALONE is sufficient. Stateme

21、nts (1) and (2) TOGETHER are NOT sufficient.【解析】：B條件1單獨不充分，因為求出的n有2個值。條件2單獨充分：能求出一個唯一值（可以用試算）n=3.【注意】：如果條件2的方程的解>1個，則看1）+2）取交集后是否能夠確定唯一值，如果可以，充分選C！（2）“Is”型：能夠確定回答yes或確定回答no都叫充分；可能回答yes也可能回答no叫不充分。Eg：相關考題（ID 2426）：If s4v3x7 < 0, is svx < 0?(1) v < 0(2) x > 0 Stateme

22、nt (1) ALONE is sufficient, but statement (2) alone is not sufficient.Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. EACH statement ALONE is sufficient. Statements (1) and (2) TOGETHER a

23、re NOT sufficient.【解析】：E本題知道v或x都沒有用，關鍵是s，因為題干已經可以確定vx<0了，所以，最終取決于s與0的關系，每個選項單獨以及結合起來都得不到s的信息，所以對于問題依然可能回答yes也可能回答no，因此無論如何都無法充分。III GMAT數學備考策略 首先：水平測試用PREP模考軟件數學部分測試一下：1） 如果能夠保證錯誤在3個以如果錯誤率超過1）的標準，或做題感覺很艱難（包括pace不穩定、讀題困難、題目思路把握不準確，etc），就按照如下三個層次來，在進行過程中，可以不斷用I的三個標準來判斷自己的進步和水平現狀，當找到相應感覺以后，就可以進入

24、下一個層次。GMAT數學備考的三個層次：1. 基礎訓練與錯誤點的尋找：OG1）OG review + DS和PS題目開始前的guide（DS是P273-276：了解出題規則），只有知己知彼才能百戰百勝。2）OG DS和PSDS160道，PS250道左右。分別把后面的100道做一遍，總結出自己的理解問題，這是基礎積累過程；A）如果各做100道：一次做完；如果都做完，就分2次完成，兩次的時間間隔不能太長，DS和PS搭配著來B）錯題總結：按照錯誤類型總結a）思維陷阱b）馬虎問題c）理解問題：并把阻礙理解的表達積累起來e）“DS的充分性”沒有把握好2. 理解能力訓練、pace訓練和知識點遺忘的克服：P

25、REP數學的破解（博森小班專區資料下載會有題目和部分講解的下載）（1） 資料：PREP破解 DS和PS最接近實戰的英文題（2） 怎么練：A） 每天37道，自己組合成套題配合著語文和作文來做，計時。B） 每天做完以后：總結錯題，猜的但猜對了的不管。按照錯誤類型進行總結：馬虎問題、思維陷阱、理解問題、知識點遺忘。尤其是知識點遺忘部分，建議把相應知識點的題目放在一起，積累到一定程度以后，會發現這一類知識點的出題思路和解題思路。C） 定時復習。（3） 練到什么程度：當發現3個標準的題感有了，就可以酌量減少，一周做2套什么的維持下感覺，根據自己的模考計劃而定。哪部分差做哪部分，時間緊的建議做完DS 2個

26、practice，PS practice1。3. 思維訓練：機經（1） 資料：當月JJ；if沒有，就用上月JJ（2） 對待JJ的心態：不是背答案，因為考場壓力可能迫使你完全忘記了答案。平時反復整理JJ的目的是讓你實現以下幾個方面：A）找到自己知識點的漏洞：練習方法我下面會講B）熟悉GMAC近期出題的思路方向：JJ的趨勢較紅書時代有所變化，這就是為什么用JJ的參考價值更大。以這個出題方向為綱引導你形成一種思想套路之類的東西，也就是：看到這類題就會自然而然地產生一個思考的方向，且這個方向90%以上是準確的。【經驗】：考場上，特別是有JJ時，很可能做得比較好，此時會遇到一些新的難題，這些題雖然陌生，

27、一定逃不出你整理過的某個知識點，運用做JJ時給你的感覺和思路，一定可以激發平時沒有的考場靈感，這就是數學和語文最大的不同。C）提高考場效率：一定是建立在水到渠成的基礎上。不是直接背了就去，除非心態極佳不怕變體或記憶力超群且識別變體的能力超群。（3）目標：最后上考場的感覺是JJ的思路已經進入了骨髓，覺得是不上51都難的感覺。（4）如何使用相應月份的JJ：1）自己先做一遍：這一遍就是找出自己的錯題，同時按如下兩條線進行分類2）無需按照PS或DS來分。兩條線A）錯誤類型：a）馬虎問題和理解問題：前者：如果時間不夠充裕的，就按我后面說的方式進行，我后面會專門講數學的備考后者：基礎不好且有時間的可以看看

28、紅書；沒有時間的就按照我說的備考進行積累和熟練為主。b）思維陷阱：c）知識點遺忘：單獨一部分進行d）DS充分性把握不好e）懸而未決：有爭議的；大家都搞不定的難題f）記住答案的：有些題目需要大量計算的，可以先用計算器算好了，直接背，不是刻意，多看幾遍一定就印象深刻了。B）知識點類型：我在10.16的答疑部分的講義有所演示如何進行這部分分類 【注意幾點】：A） 馬虎問題：我覺得比較好的：整理JJ的工作可以和做PREP同步進行。所以，就把自己這段時間以來的PREP的錯題（之前已經分類）中馬虎問題集中起來做一遍，總結出一種對GMAT數學prefer的一些馬虎點的感覺，然后再拿出JJ中的馬虎問題看2遍，

29、記住自己容易出錯的地方B）理解問題：做PREP時就要注意積累一些自己不熟悉的表達，做JJ時遇到理解問題，繼續積累收藏，考前看看就OK了。C）思維陷阱：以JJ為綱，按知識點整理出一類題自己怎么愛犯錯的。如果基礎再差一點兒，可以加上PREP的相同類型錯誤的題目一起整理。考前反復看幾遍，把這種敏感融入到題感之中。（比如，概率中的有沒有放回，是否是獨立事件；余數問題：）。D）懸而未決：有爭議的、大家都沒轍的難題放了，依靠考場靈感。E）知識點遺忘：看看自己薄弱的知識點在哪一部分，有針對性地補博森的數學書“知識點講解”部分或任意下載一些整理好的數學知識點中文總結即可，OG的math review是基礎僅僅

30、提供廣度和系統性的了解，但在這個范圍內各考點的深度需要利用中文資料自己進一步彌補，建議使用好google和維基百科等網絡工具來查漏補缺。 （4）重視討論帖：自己先看，通過整理機井+看討論后依然不明白的，放到答疑專區，并并寫清楚您的問題是什么，我們好有的放矢地解決。 （5）考前把自己最后的錯題分類總結快速看一遍：早上考的，頭晚系統看看；下午考的，第二天上午看看。主要看什么：自己之前解決的難題，簡單的就不用看了；有爭議的也看看：不是記住答案，而是告訴自己，遇到這些要小心，這是沒有確定的，需要我自己好好思考的，不要考場上亂點。這一遍會讓機經帶給你的解題感覺在腦中清晰和系統化，有助于臨陣不亂。 4.

31、考場上：不要去想GMAC是怎么評分的，一切都是未知和徒勞，專氣致柔如嬰兒是在做好上述準備后獲得高分的唯一要訣。5. 對于知識基礎扎實、題目閱讀理解順暢、pace很好的同學：備考前把OG的math review過一遍，直接進入JJ整理（當月或前月均可，經驗反復證明：機經對于前面月份相同題目的重復經常存在），在此基礎上，在上述4步中挑選你認為有必要的步驟進行補充訓練即可。 IV 附錄： 附件1： 理解問題專題集錦【注】：以下題目均來源于PREP破解1和2，下面只分析讀題，有興趣解題的同學可以查閱破解版相應題目的答案。 I 比例問題、比較問題+集合問題（含濃度問題）【怎么讀】：1. 比例問題：讀出分

32、子分母1）遇到percentage和fraction：注意跟在這兩個詞后的of后的部分（包含其修飾語）就是分母；2）ratio：ratio of A to BA是分子，B是分母2. 集合：讀出分類標準，并且能夠通過英文表述準確識別是否是全集、有沒有交集或并集1）一個標準分類的：通常用韋恩圖或公式直接求解2）兩個標準分類的：通常用二維表解決較為簡單明了3. 比較問題：準確讀出比較對象 96. 10591-!-item-!-187;#058&007292According to the directions on a can of frozen orange juice conce

33、ntrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice.l1 How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juicel2 ?(A) 25(B) 34(C) 50(D) 67(E) 100 142. 14580-!-item-!-187;#058&010013The rate of a certain chemical

34、 reaction is directly proportional to the square of the concentration of chemical A present and inversely proportional to the concentration of chemical B present.l3 If the concentration of chemical B is increased by 100 percent, which of the following is closest to the percent change in the concentr

35、ation of chemical A required to keep the reaction rate unchanged?(A) 100% decrease(B) 50% decrease(C) 40% decrease(D) 40% increase(E) 50% increase 164. 17177-!-item-!-187;#058&011044A certain scholarship committee awarded scholarships in the amounts of $1,250, $2,500, and $4,000l4 . The comm

36、ittee awarded twice as many $2,500 scholarships as $4,000 scholarships, and it awarded three times as many $1,250 scholarships as $2,500scholarships. l5 If a total of $37,500 was awarded in $1,250 scholarships, how many $4,000 scholarships were awarded? (A) 5(B) 6(C) 9(D) 10(E) 15 165. 16466-!-item-

37、!-187;#058&010795Of the 1,400 college teachers surveyed, 42 percent said that they considered engaging in research an essential goal. How many of the college teachers surveyed were women?(1) In the survey, 36 percent of the men and 50 percent of the women said that they considered engaging i

38、n research an essential goal.l6(2) In the survey, 288 men said that they considered engaging in research an essential goal.【解】：A1）破題：A）理解的關鍵：見批注B）破題：這是一個標準的二維表問題2）思路：見下表 FMT E 50%x;700 E取非 T X 1400-x 1400 36*(1400-x);288 *42%【NOTE】：黑色字為題干已知；綠色字為條件1已知；紅色字為條件2已知。 179. 17750-!-item-!-187;#058&0

39、11285A manufacturer conducted a survey to determine how many people buy products P and Q.l7 What fraction of the people surveyed said that they buy neither product P nor product Q ?(1)1/3 of the people surveyed said that they buy product P but not product Q.(2) 1/2 of the people surveyed said that t

40、hey buy product Q. 202. 19528-!-item-!-187;#058&012279Each employee of Company Z is an employee of either Division X or Division Y, but not both. If each division has some part-time employees, is the ratio of the number of full-timeemployees to the number of part-time employees greater for D

41、ivision X than for Company Zl8 ?(1) The ratio of the number of full-time employees to the number of part-time employees is less for Division Y than for Company Z.(2) More than half of the full-time employees of Company Z are employees of Division Xl9 , and more than half of the part-time employees o

42、f Company Z are employees of Division Yl10 . 212. 20491-!-item-!-187;#058&012823This morning, a certain sugar container was full. Since then some of the sugar from this container was used to make cookies. If no other sugar was removed from or added to the container, by what percent did the a

43、mount of sugar in the container decreasel11 ?(1) The amount of sugar in the container after making the cookies would need to be increased by 30 percent to fill the container.(2) Six cups of sugar from the container were used to make the cookies. 85. 9649-!-item-!-187;#058&007038Of the 800 em

44、ployees of Company X, 70 percent have been with the company for at least ten years. If y of these "long-term" members were to retire and no other employee changes were to occur, what value of y would reduce the percent of "long-term" employees in the company to 60

45、 percent?l12 (A) 200(B) 160(C) 112(D) 80(E) 56 88. 9789-!-item-!-187;#058&007104In May Mrs. Lees earnings were 60 percent of the Lee familys total income. In June Mrs. Lee earned 20 percent more than in May. l13 If the rest of the familys income was the same both months, then, in June, Mrs.

46、Lees earnings were approximately what percent of the Lee familys total income? (A) 64%(B) 68%(C) 72%(D) 76%(E) 80% 176. 17259-!-item-!-187;#058&011402In 1995 Division A of Company X had 4,850 customers. If there were 86 service errors in Division A that year, what was the service-error rate,

47、 in number of service errors per 100 customersl14 , for Division B of Company X in 1995 ?(1) In 1995 the overall service-error rate for Divisions A and B combined was 1.5 service errors per 100 customers.(2) In 1995 Division B had 9,350 customers, none of whom were customers of Division A.II 工程問題【怎么

48、讀】：讀出模型的幾個元素工程問題通用模型：1/a + 1/b +1/c+ = 1/t原理：×（va+vb+）=T（工作總量） 105. 11075-!-item-!-187;#058&007490Two water pumps, working simultaneously at their respective constant rates, took exactly 4 hours to fill a certain swimming pool. If the constant rate of one pump was 1.5 times the constant

49、 rate of the other, how many hours would it have taken the faster pump to fill the pool if it had worked alone at its constant rate? (A) 5(B)(C)(D) 6(E) 5. 1353-!-item-!-187;#058&000886Working alone at its own constant rate, a machine seals k cartons in 8 hours, and working alone at its own

50、constant rate, a second machine seals k cartons in 4 hours. If the two machines, each working at its own constant rate and for the same period of time, together sealed a certain number of cartons, what percent of the cartons were sealed by the machine working at the faster ratel15 ? (A) 25%(B)(C) 50

51、%(D)(E) 75% 179. 17563-!-item-!-187;#058&011544Working independently at their respective constant rates, pumps X and Y took 48 minutes to fill an empty tank with water. What fraction of the water in the full tank came from pump X ?(1) Working alone at its constant rate, pump X would have tak

52、en 80 minutes to fill the tank with water.(2) Working alone at its constant rate, pump Y would have taken 120 minutes to fill the tank with water. III 描述統計【怎么讀】：熟悉描述統計的相關術語及其公式的表達方式，找到各個統計指標的關系比如：average和SD 110. 11364-!-item-!-187;#058&007646The residents of Town X participated in a survey t

53、o determine the number of hours per week each resident spent watching television. The distribution of the results of the survey had a mean of 21 hours and a standard deviation of 6 hours. The number of hours that Pat, a resident of Town X, watched television last week was between 1 and 2 standard de

54、viationsbelow the mean. Which of the following could be the number of hours that Pat watched television last week? (A) 30(B) 20(C) 18(D) 12(E) 6 這個題的重點理解題意：在the number of hours per week Pat watched TV was between 1 and 2 standard deviations below the mean.one standard deviation below the mean = 21-6

55、=15two standard deviations below the mean = 21-6*2=9所以Pat看電視的時間在9小時和15小時之間，只有答案D符合。【小結】：標準差萬變不離其宗的公式/Mean-某個element/=x*標準差【x為標準差的倍數或個數】如果是above：mean+；反之：mean- IV 排列組合、概率【怎么讀】：從英文表述中識別出是求的排列組合三個基本類型的哪一類；概率問題準確判斷分子和分母117. 11706-!-item-!-187;#058&007820A certain office supply store stocks 2 siz

56、es of self-stick notepads, each in 4 colors: blue, green, yellow, or pink. The store packs the notepads in packages that contain either 3 notepads of the same size and the same color or 3 notepads of the same size and of 3 different colors. l16 If the order in which the colors are packed is not cons

57、idered, how many different packages of the types described above are possible? (A) 6(B) 8(C) 16(D) 24(E) 32 1. 246-!-item-!-187;#058&000117Tanya prepared 4 different letters to be sent to 4 different addresses. For each letter, she prepared an envelope with its correct address. If the 4 lett

58、ers are to be put into the 4 envelopes at random, what is the probability that only 1 letter will be put into the envelope with its correct address?排列問題 25. 3619-!-item-!-187;#058&003382A fast-food company plans to build 4 new restaurants. If there are 12 sites that satisfy the companys criteria for location of new restaurants, in how many different ways can