SQL學習例子經典_第1頁
SQL學習例子經典_第2頁
SQL學習例子經典_第3頁
SQL學習例子經典_第4頁
SQL學習例子經典_第5頁
已閱讀5頁,還剩7頁未讀 繼續免費閱讀

下載本文檔

版權說明:本文檔由用戶提供并上傳,收益歸屬內容提供方,若內容存在侵權,請進行舉報或認領

文檔簡介

1、表架構Student(S#,Sname,Sage,Ssex) 學生表Course(C#,Cname,T#) 課程表SC(S#,C#,score) 成績表Teacher(T#,Tname) 教師表建表語句按 Ctrl+C 復制代碼按 Ctrl+C 復制代碼插入測試數據語句按 Ctrl+C 復制代碼按 Ctrl+C 復制代碼問題問題: 1、查詢“001”課程比“002”課程成績高的所有學生的學號; select a.S# from (select s#,score from SC where C#=001) a,(select s#,score from SC where C#=002) b wh

2、ere a.scoreb.score and a.s#=b.s#; 2、查詢平均成績大于60分的同學的學號和平均成績; select S#,avg(score) from sc group by S# having avg(score) 60; 3、查詢所有同學的學號、姓名、選課數、總成績; select Student.S#,Student.Sname,count(SC.C#),sum(score) from Student left Outer join SC on Student.S#=SC.S# group by Student.S#,Sname 4、查詢姓“李”的老師的個數; sel

3、ect count(distinct(Tname) from Teacher where Tname like 李%; 5、查詢沒學過“葉平”老師課的同學的學號、姓名; select Student.S#,Student.Sname from Student where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname=葉平); 6、查詢學過“001”并且也學過編號“002”課程的同學的學號、姓名;

4、select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#=001and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#=002); 7、查詢學過“葉平”老師所教的所有課的同學的學號、姓名; select S#,Sname from Student where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T

5、#=Course.T# and Teacher.Tname=葉平 group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname=葉平); 8、查詢課程編號“002”的成績比課程編號“001”課程低的所有同學的學號、姓名; Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S#

6、and SC_2.C#=002) score2 from Student,SC where Student.S#=SC.S# and C#=001) S_2 where score2 60); 10、查詢沒有學全所有課的同學的學號、姓名; select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) =60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分數 FROM SC T,Course

7、where t.C#=course.C# GROUP BY t.C# ORDER BY 100 * SUM(CASE WHEN isnull(score,0)=60 THEN 1 ELSE 0 END)/COUNT(*) DESC 20、查詢如下課程平均成績和及格率的百分數(用1行顯示): 企業管理(001),馬克思(002),OO&UML (003),數據庫(004) SELECT SUM(CASE WHEN C# =001 THEN score ELSE 0 END)/SUM(CASE C# WHEN 001 THEN 1 ELSE 0 END) AS 企業管理平均分 ,100 * SUM

8、(CASE WHEN C# = 001 AND score = 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = 001 THEN 1 ELSE 0 END) AS 企業管理及格百分數 ,SUM(CASE WHEN C# = 002 THEN score ELSE 0 END)/SUM(CASE C# WHEN 002 THEN 1 ELSE 0 END) AS 馬克思平均分 ,100 * SUM(CASE WHEN C# = 002 AND score = 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = 002 THEN 1

9、ELSE 0 END) AS 馬克思及格百分數 ,SUM(CASE WHEN C# = 003 THEN score ELSE 0 END)/SUM(CASE C# WHEN 003 THEN 1 ELSE 0 END) AS UML平均分 ,100 * SUM(CASE WHEN C# = 003 AND score = 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = 003 THEN 1 ELSE 0 END) AS UML及格百分數 ,SUM(CASE WHEN C# = 004 THEN score ELSE 0 END)/SUM(CASE C# WH

10、EN 004 THEN 1 ELSE 0 END) AS 數據庫平均分 ,100 * SUM(CASE WHEN C# = 004 AND score = 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = 004 THEN 1 ELSE 0 END) AS 數據庫及格百分數 FROM SC 21、查詢不同老師所教不同課程平均分從高到低顯示 SELECT max(Z.T#) AS 教師ID,MAX(Z.Tname) AS 教師姓名,C.C# AS 課程,MAX(C.Cname) AS 課程名稱,AVG(Score) AS 平均成績 FROM SC AS T,Cou

11、rse AS C ,Teacher AS Z where T.C#=C.C# and C.T#=Z.T# GROUP BY C.C# ORDER BY AVG(Score) DESC 22、查詢如下課程成績第 3 名到第 6 名的學生成績單:企業管理(001),馬克思(002),UML (003),數據庫(004) 學生ID,學生姓名,企業管理,馬克思,UML,數據庫,平均成績 SELECT DISTINCT top 3 SC.S# As 學生學號, Student.Sname AS 學生姓名 , T1.score AS 企業管理, T2.score AS 馬克思, T3.score AS U

12、ML, T4.score AS 數據庫, ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 總分 FROM Student,SC LEFT JOIN SC AS T1 ON SC.S# = T1.S# AND T1.C# = 001 LEFT JOIN SC AS T2 ON SC.S# = T2.S# AND T2.C# = 002 LEFT JOIN SC AS T3 ON SC.S# = T3.S# AND T3.C# = 003 LEFT JOIN SC AS T4

13、ON SC.S# = T4.S# AND T4.C# = 004 WHERE student.S#=SC.S# and ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) NOT IN (SELECT DISTINCT TOP 15 WITH TIES ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) FROM sc LEFT JOIN sc AS T1 ON sc.S#

14、 = T1.S# AND T1.C# = k1 LEFT JOIN sc AS T2 ON sc.S# = T2.S# AND T2.C# = k2 LEFT JOIN sc AS T3 ON sc.S# = T3.S# AND T3.C# = k3 LEFT JOIN sc AS T4 ON sc.S# = T4.S# AND T4.C# = k4 ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC); 23、統計列印各科成績,各分數段人數:課程ID,課

15、程名稱,100-85,85-70,70-60, 60 SELECT SC.C# as 課程ID, Cname as 課程名稱 ,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS 100 - 85 ,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS 85 - 70 ,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS 70 - 60 ,SUM(CASE WHEN score T2.平均成績

16、) as 名次, S# as 學生學號,平均成績 FROM (SELECT S#,AVG(score) 平均成績 FROM SC GROUP BY S# ) AS T2 ORDER BY 平均成績 desc; 25、查詢各科成績前三名的記錄:(不考慮成績并列情況) SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數 FROM SC t1 WHERE score IN (SELECT TOP 3 score FROM SC WHERE t1.C#= C# ORDER BY score DESC ) ORDER BY t1.C#; 26、查詢每門課程被選修

17、的學生數 select c#,count(S#) from sc group by C#; 27、查詢出只選修了一門課程的全部學生的學號和姓名 select SC.S#,Student.Sname,count(C#) AS 選課數 from SC ,Student where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1; 28、查詢男生、女生人數 Select count(Ssex) as 男生人數 from Student group by Ssex having Ssex=男; Select count

18、(Ssex) as 女生人數 from Student group by Ssex having Ssex=女; 29、查詢姓“張”的學生名單 SELECT Sname FROM Student WHERE Sname like 張%; 30、查詢同名同性學生名單,并統計同名人數 select Sname,count(*) from Student group by Sname having count(*)1; 31、1981年出生的學生名單(注:Student表中Sage列的類型是datetime) select Sname, CONVERT(char (11),DATEPART(year

19、,Sage) as age from student where CONVERT(char(11),DATEPART(year,Sage)=1981; 32、查詢每門課程的平均成績,結果按平均成績升序排列,平均成績相同時,按課程號降序排列 Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ; 33、查詢平均成績大于85的所有學生的學號、姓名和平均成績 select Sname,SC.S# ,avg(score) from Student,SC where Student.S#=SC.S# group by

20、SC.S#,Sname having avg(score)85; 34、查詢課程名稱為“數據庫”,且分數低于60的學生姓名和分數 Select Sname,isnull(score,0) from Student,SC,Course where SC.S#=Student.S# and SC.C#=Course.C# and Course.Cname=數據庫and score =70 AND SC.S#=student.S#; 37、查詢不及格的課程,并按課程號從大到小排列 select c# from sc where scor e 80 and C#=003; 39、求選了課程的學生人數

21、select count(*) from sc; 40、查詢選修“葉平”老師所授課程的學生中,成績最高的學生姓名及其成績 select Student.Sname,score from Student,SC,Course C,Teacher where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname=葉平 and SC.score=(select max(score)from SC where C#=C.C# ); 41、查詢各個課程及相應的選修人數 select count(*) from sc gr

22、oup by C#; 42、查詢不同課程成績相同的學生的學號、課程號、學生成績 select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# B.C# ; 43、查詢每門功成績最好的前兩名 SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數 FROM SC t1 WHERE score IN (SELECT TOP 2 score FROM SC WHERE t1.C#= C# ORDER BY score DESC ) ORDER BY t1.C#; 44、統計

23、每門課程的學生選修人數(超過10人的課程才統計)。要求輸出課程號和選修人數,查詢結果按人數降序排列,查詢結果按人數降序排列,若人數相同,按課程號升序排列 select C# as 課程號,count(*) as 人數 from sc group by C# order by count(*) desc,c# 45、檢索至少選修兩門課程的學生學號 select S# from sc group by s# having count(*) = 2 46、查詢全部學生都選修的課程的課程號和課程名 select C#,Cname from Course where C# in (select c# f

24、rom sc group by c#) 47、查詢沒學過“葉平”老師講授的任一門課程的學生姓名 select Sname from Student where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname=葉平); 48、查詢兩門以上不及格課程的同學的學號及其平均成績 select S#,avg(isnull(score,0) from SC where S# in (select S# from SC where score 2)grou

25、p by S#; 49、檢索“004”課程分數小于60,按分數降序排列的同學學號 select S# from SC where C#=004and score 53. 查詢借閱了水滸一書的讀者,輸出姓名及班級-實現代碼:SELECT * FROM CARD cWHERE EXISTS( SELECT * FROM BORROW a,BOOKS b WHERE a.BNO=b.BNO AND b.BNAME=N水滸 AND a.CNO=c.CNO) 4. 查詢過期未還圖書,輸出借閱者(卡號)、書號及還書日期-實現代碼:SELECT * FROM BORROW WHERE RDATE0INSER

26、T BORROW_SAVE SELECT i.*FROM INSERTED i,BOOKS bWHERE i.BNO=b.BNO AND b.BNAME=N數據庫技術及應用 12. 建立一個視圖,顯示力01班學生的借書信息(只要求顯示姓名和書名)-實現代碼:CREATE VIEW V_VIEWASSELECT a.NAME,b.BNAMEFROM BORROW ab,CARD a,BOOKS bWHERE ab.CNO=a.CNO AND ab.BNO=b.BNO AND a.CLASS=N力0113. 查詢當前同時借有計算方法和組合數學兩本書的讀者,輸出其借書卡號,并按卡號升序排序輸出-實現

27、代碼:SELECT a.CNOFROM BORROW a,BOOKS bWHERE a.BNO=b.BNO AND b.BNAME IN(N計算方法,N組合數學)GROUP BY a.CNOHAVING COUNT(*)=2ORDER BY a.CNO DESC 14. 假定在建BOOKS表時沒有定義主碼,寫出為BOOKS表追加定義主碼的語句-實現代碼:ALTER TABLE BOOKS ADD PRIMARY KEY(BNO) 15.1 將NAME最大列寬增加到10個字符(假定原為6個字符)-實現代碼:ALTER TABLE CARD ALTER COLUMN NAME varchar(10

溫馨提示

  • 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
  • 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯系上傳者。文件的所有權益歸上傳用戶所有。
  • 3. 本站RAR壓縮包中若帶圖紙,網頁內容里面會有圖紙預覽,若沒有圖紙預覽就沒有圖紙。
  • 4. 未經權益所有人同意不得將文件中的內容挪作商業或盈利用途。
  • 5. 人人文庫網僅提供信息存儲空間,僅對用戶上傳內容的表現方式做保護處理,對用戶上傳分享的文檔內容本身不做任何修改或編輯,并不能對任何下載內容負責。
  • 6. 下載文件中如有侵權或不適當內容,請與我們聯系,我們立即糾正。
  • 7. 本站不保證下載資源的準確性、安全性和完整性, 同時也不承擔用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。

評論

0/150

提交評論