????????????????線???????????封??????????????????密???????????????????????????????????線???????????封??????????????????密???????????????????級班業專系號學名姓???????????????????????????題???????不?內?線?封?密?EQ\*jc3\*hps31\o\al(\s\up7(?),?)?????????????????????????○EQ\*jc3\*hps31\o\al(\s\up8(○),密)2.所有答案請直接答在試卷上封評卷人------------------------斷下列命題是否正確,正確的在其后面括號內填上“V封評卷人------------------------EQ\*jc3\*hps31\o\al(\s\up6(○),裝)評卷人每小題列出的四個選項中只有一個是符合題目要求的，請將其代碼○復查人填在題后的括號內。錯選或未選均無分）T2--------------------------○答案直接填入括號內）評卷人EQ\*jc3\*hps36\o\al(\s\up15(2),4)EQ\*jc3\*hps36\o\al(\s\up15(1),3)-1EQ\*jc3\*hps36\o\al(\s\up13(1),2)EQ\*jc3\*hps35\o\al(\s\up9(0),1)EQ\*jc3\*hps35\o\al(\s\up9(2),2)EQ\*jc3\*hps35\o\al(\s\up9(2),0)22（7分）（7分）○評卷人○密0-2-2-4+10-2-0-2-2-2-20-2-2（4分）（4分）-2-20-2-2-20（7分）（7分）|2EQ\*jc3\*hps35\o\al(\s\up13(2),1)EQ\*jc3\*hps35\o\al(\s\up13(1),2)EQ\*jc3\*hps35\o\al(\s\up13(2),3)EQ\*jc3\*hps35\o\al(\s\up13(2),1)EQ\*jc3\*hps35\o\al(\s\up13(0),1)EQ\*jc3\*hps35\o\al(\s\up13(4),2)EQ\*jc3\*hps35\o\al(\s\up13(2),4)EQ\*jc3\*hps35\o\al(\s\up13(4),6)EQ\*jc3\*hps35\o\al(\s\up13(6),3)○訂「9|訂「9|54（4分）（4分）|○AB=|211-1021-1-2]○(a(a|EQ\*jc3\*hps35\o\al(\s\up15(a),2)EQ\*jc3\*hps35\o\al(\s\up15(1),0)EQ\*jc3\*hps35\o\al(\s\up15(1),1)EQ\*jc3\*hps35\o\al(\s\up15(1),1)EQ\*jc3\*hps35\o\al(\s\up15(+),3)（5分）（7分）（7分）「10-2]「10-2]「10-2]EQ\*jc3\*hps36\o\al(\s\up16(6),3)EQ\*jc3\*hps36\o\al(\s\up16(4),2)EQ\*jc3\*hps36\o\al(\s\up16(4),2)EQ\*jc3\*hps36\o\al(\s\up16(0),0)EQ\*jc3\*hps36\o\al(\s\up16(0),2)EQ\*jc3\*hps36\o\al(\s\up16(0),8)EQ\*jc3\*hps36\o\al(\s\up16(0),0)EQ\*jc3\*hps36\o\al(\s\up16(2),0)EQ\*jc3\*hps36\o\al(\s\up16(8),0)○評卷人評卷人1η○η密13|||,3|||,求該方程組的通解.------------------1試確定實數a的取值范圍,使相應的二次型f正定.