1、問題一：懸臂梁受重力作用發(fā)生大變形，求其固有頻率。基本過程:1、建模2、靜力分析NLGEOM,ONSTRES,ON3、求靜力解4、開始新的求解：modalSTRES,ONUPCOORD,1,ON修正坐標(biāo)SOLVE.5、擴(kuò)展模態(tài)解6、察看結(jié)果/PREP7ET,1,BEAM189MPTEMP,!使用beam189梁單元MPTEMP,1,0MPDATA,EX,1,210e9MPDATA,PRXY,1,0.3MPDATA,DENS,1,7850SECTYPE,1,BEAM,RECT,secA,0SECOFFSET,CENT!定義梁截面secASECDATA,0.005,0.01,0,0,0,0,0,0

2、,0,0K,!建模與分網(wǎng)K,2,K,2,1,LSTR,1,LATT,1,1,LESIZE,1,20,13,1LMESH,FINISH/SOL!靜力大變形求解ANTYPE,0NLGEOM,1PSTRES,ON!計及預(yù)應(yīng)力效果DK,1,0,ALL,ACEL,0,9.8,0,TIME,1!只考慮重力作用AUTOTS,1NSUBST,20,1KBC,0SOLVEFINISH/SOLUTIONANTYPE,2!進(jìn)行模態(tài)求解MSAVE,0MODOPT,LANB,10MXPAND,10,0PSTRES,1打開預(yù)應(yīng)力效應(yīng)MODOPT,LANB,10,0,0,OFFUPCOORD,1,ONPSOLVE,TRIA

3、NG!修正坐標(biāo)以得到正確的應(yīng)力!三角化矩陣PSOLVE,EIGLANBFINISH/SOLUEXPASS,1!擴(kuò)展模態(tài)解PSOLVE,EIGEXPFINISH/POST1SET,LIST!觀察結(jié)果FINISHsecA問題二：循環(huán)對稱結(jié)構(gòu)模態(tài)分析這是ANSYSHELFH的例子，但那個命令流似乎有些問題，下面是整理過的命令流。基本過程:1、建模2、definecyclic3、定義約束4、求模態(tài)解5、展開并察看結(jié)果r1=5!建模r2=10d1=2nsect=24alpha_deg=360/nsectalpha_rad=2*acos(-1)/nsect/prep7csys,1k,1,0,0,0k,2,

4、0,0,d1k,3,r1,0,0k,4,r1,0,d13,4arotat,1,1,2,alpha_deg/2k,7,r2,0,0k,8,r2,0,d17,8arotat,5,1,2,alpha_deg/2arotat,2,1,2,alpha_deg/2arotat,6,1,2,alpha_deg/2a,5,6,10,9mshkey,1et,1,181r,1,0.20r,2,0.1mp,ex,1,10e6mp,prxy,1,0.3mp,dens,1,1e-4esize,0.5asel,1,4aatt,1asel,5aatt,2allselCYCLIC,CYCLIC!定義基本扇區(qū)AMESH,all

5、!分網(wǎng)FINISH/SOL!求模態(tài)解ANTYPE,2MODOPT,LANB,10MXPAND,10,0PSTRES,0MODOPT,LANB,10,0,0,OFFDK,5,0,UZ,SOLVEFINISH/POST1SET,LISTSET,1,4,/CYCEXPAND,ONPLNS,U,SUM!觀察擴(kuò)1FINISH問題三：三角平臺受諧波載荷作用，求結(jié)構(gòu)響應(yīng)諧波載荷為作用在平臺上面一點的集中力，幅值為10N,頻率范圍5Hz70Hz基本過程：1、建模求模態(tài)解3、用模態(tài)疊加法作諧分析觀察結(jié)果/PREP7!建模ET,1,BEAM189ET,2,SHELL93R,1,0.01,MP,EX,1,210e9

6、MP,PRXY,1,0.3MP,DENS,1,7850SECTYPE,1,BEAM,RECT,secA,0SECOFFSET,CENTSECDATA,0.005,0.008,0,0,0,0,0,0,0,0K,-0.5,K,0.5,K,1,K,1,1,K,-0.5,1,K,0.5,1,K,0.5,A,4,5,6LSTR,1,5LSTR,3,4LSTR,2,6LSEL,S,LINE,4,6LATT,1,1,1,7,1LSEL,ALLLESIZE,ALL,10,1LMESH,4,6TYPE,2MSHAPE,0,2DMSHKEY,1AMESH,1FINISH/SOL!為了使用模態(tài)疊加法諧分析ANTYP

7、E,2MODOPT,LANB,20!先取結(jié)構(gòu)前20階模態(tài)MXPAND,20,0MODOPT,LANB,20,0,0,OFFKSEL,S,KP,1,3DK,ALL,0,ALL,SOLVEFINISH!/POST1!最好事先看一下模態(tài)結(jié)果!SET,LIST!以了解模態(tài)頻率范圍!FINISH/SOL!模態(tài)疊加法諧響應(yīng)分析ANTYPE,3HROPT,MSUPHROUT,ONHROPT,MSUP,20,HROUT,ON,OFF,0F,177,FY,-10,!施加10N的力在節(jié)點177的負(fù)丫方向HARFRQ,5,70,!載荷的強(qiáng)制頻率范圍NSUBST,200,KBC,1ALPHAD,5,SOLVEFINI

8、SH/POST26FILE,rfrqNUMVAR,20NSOL,2,139,U,Y,PLVAR,2FINISHI問題四：三角平臺受一地震譜激勵，求應(yīng)力分布和支反力基本過程：1、建模2、求模態(tài)解3、求譜解4、擴(kuò)展模態(tài)5、模態(tài)合并6、觀察結(jié)果/PREP7!建模ET,1,BEAM189ET,2,SHELL93R,1,0.01,MP,EX,1,210e9MP,PRXY,1,0.3MP,DENS,1,7850SECTYPE,1,BEAM,RECT,secA,0SECOFFSET,CENTSECDATA,0.005,0.008,0,0,0,0,0,0,0,0K,-0.5,K,0.5,K,1,K,1,1,K

9、,-0.5,1,K,0.5,1,K,0.5,A,4,5,6LSTR,1,5LSTR,3,4LSTR,2,6LSEL,S,LINE,4,6LATT,1,1,1,7,1LSEL,ALLLESIZE,ALL,10,1LMESH,4,6TYPE,2MSHAPE,0,2DMSHKEY,1AMESH,1FINISH/SOL!取前十階模態(tài)ANTYPE,2MODOPT,LANB,10KSEL,S,KP,1,3DK,ALL,0,ALL,SOLVEFINISH/SOL!譜分析ANTYPE,8SPOPT,SPRS,10,1SVTYP,3SED,0,1,0,!給出激勵方向FREQ,0.25,1.34,6.73,14.

10、6,28.9,0,0,0,0!激勵譜SV,0,0.00073,0.00016,0.00034,0.00034,0.00052,SOLVEFINISH/SOL!擴(kuò)展模態(tài)ANTYPE,2EXPASS,1MXPAND,10,0,0,1,0.001,SOLVEFINISH/SOL!模態(tài)合并ANTYPE,8SRSS,0.001,DISPSOLVE/POST1!觀察結(jié)果SET,LIST/INPUT,mcomPRRSOL,FFINISH問題五：三角平臺受時程載荷作用，求應(yīng)力分布和變形過程基本過程：1、建模施加隨時間變化載荷，定義載荷步3、求解在POST1和POST26中觀察結(jié)果/PREP7!建模ET,1,B

11、EAM189ET,2,SHELL93R,1,0.01,MP,EX,1,210e9MP,PRXY,1,0.3MP,DENS,1,7850SECTYPE,1,BEAM,RECT,secA,0SECOFFSET,CENTSECDATA,0.005,0.008,0,0,0,0,0,0,0,0K,-0.5,K,0.5,K,1,K,1,1,K,-0.5,1,K,0.5,1,K,0.5,A,4,5,6LSTR,1,5LSTR,3,4LSTR,2,6LSEL,S,LINE,4,6LATT,1,1,1,7,1LSEL,ALLLESIZE,ALL,10,1LMESH,4,6TYPE,2MSHAPE,0,2DMSHKEY,1AMESH,1FINISH/SOLANTYPE,4TRNOPT,FULLKSEL,S,KP,1,3DK,ALL,0,ALL,OUTRES,ALL,1ALPHAD,5,TIME,2AUTOTS,1NSUBST,50,1KBC,0SFA,ALL,1,PRES,500LSWRITE,1,TIME,3LSWRITE,2,TIME,4SFA,ALL,1,PRES,150KBC