1、C + + 程 序 設 計 模 擬 題三、用C+語言描述下列命題1、A小于B并且A大于C2、A和B中有 個小于C3、A是奇數4、B和C中較大者與A相等5、年份Y是閏年 四、寫出下列程序的執行結果1.#include void main()int b35=11,12,13,14,15,21,22,23,24,25,31,32,33,34,35; int (*p)5;p=b;for(int j=0;j5;j+) cout*(*p+j) , ;coutendl;2.#includevoid swapl(int a,int b)int temp=a;a=b; b=temp;void swap2(int

2、*a,int*b)int temp=*a; *a=*b,*b=temp;void swap3(int*a,int*b)int*temp=a; a=b,b=temp;void swap4(int &a,int &b)int temp=a;a=b; b=temp;void main()int a=10,b=20; swapl(a,b);couta: bendl; swap2(&a,&b);couta: bendl; swap3(&a,&b);couta: bendl; swap4(a,b);couta: bendl;3. &#includev

3、oid print(int w)int i;if(w!=0)print(w-1); for(i=1;i=w;i+) coutw;coutendl;void main()print(4);4.#include#defi ne sw(x,y)xA=y;yA=x;xA=y;void main()int a=10,b=01;sw(a,b); couta,b;5.假定輸入10個整數：32，64，53，87，54，32，98，56，98，83。結果是什么？&#include void main( )int a,b,c,x; a=b=c=0;for (int k=0; kx; switch(x%3)

4、case 0:a+=x; break; case 1:b+=x; break; case 2:c+=x; break;couta b cendl;6.#include void main( )int j,k;for (j=5; j0; j-) for (k=j; k0; k-) cout*; coutendl;7. #include void main()int nNumber;int *pPointer; nNumber = 15; pPointer = &nNumber;coutnNumber is equal to : nNumberendl;*pPointer = 25;cou

5、tnNumber is equal to :nNumberendl;8.#include int *pPointer;void SomeFunction()pPointer = new int;*pPointer = 25;void main()SomeFunction();coutValue of *pPointer: *pPointerendl;delete pPointer;列程序的輸出9.#include void AddFive(int* Number)*Number = *Number + 5;void main()int nMyNumber = 18;coutMy origina

6、l number is nMyNumberendl;AddFive(&nMyNumber);coutMy new number is nMyNumberendl;10.#include void main()int Array3;Array0 = 10;Array1 = 20;Array2 = 30;int *pArray; pArray = &Array0;coutpArray points to the value.endl; cout*pArrayendl;cout*(pArray+1)endl;11.* #include int i=4;void main()couti

7、=iendl;i=5;int i;i=7;couti=iendl;couti=i;12.* #includevoid fun( );void main( )fun( );fun( );void fun( )static int a=1;int i=5;a+;i+;couti=i,a=aendl;13.& #include class Point public:Point(int xx=0, int yy=0) X=xx; Y=yy; countP+; Point(Point &p);int GetX( ) return X;int GetY( ) return Y;void G

8、etC( ) cout Object id=countPendl; private:int X,Y;static int countP;Point:Point(Point &p) X=p.X;Y=p.Y; countP+;int Point:countP=0; void main ( ) Point A(4,5);coutPoint A,A.GetX () ,A.GetY ( );A.GetC ( );Point B(A);coutPoint B,B.GetX () ,B.GetY ( );B.GetC ( );14.*#include int addDefault(int x=1,i

9、nt y=2); void fun(void);void main(void)int addDefault(int x=3,int y=4); coutaddDefault()endl; fun();int addDefault(int x, int y)coutx+y=;return x+y;void fun(void)coutaddDefault()endl;5. *#include void main() int m,n,a=3,b=3,number;number=237;m=number/5;n=number%5; coutm=mendl; coutn=nendl; a+=m;b*=n

10、;couta=aendl;coutb=bendl;6.*#include void main()int width,height,result1,result2,result3; height=3;width=5;result1=height3 & width=5;result2=height3 | width=5;result3=!(width=5);coutresult1result1endl;coutresult2result2endl;coutresult3result3endl;7.*#include void main() int i=32,j=6;double df;df

11、=i/j+2.3;coutdf=dfendl;i=df/3; couti=iendl;18. &# include int c10;void add(int x,int y)static int i=0;ci=x+y;i+;void main()int a10=1,2,3,4,5,6,7,8,9,10;int b10=10,9,8,7,6,5,4,3,2,1;int i=0,k=0;for(i=0;i10;i+) add(ai,bi);for(i=0;i10;i+) coutci ;19.#include void main()char s30=computer,mouse,key;i

12、nt i=0,k=0;coutsendl;while(si!=0)if(si=m)/通過數組名和下標引用數組元素k+;i+;couti=iendl; coutk=kendl;20.#include void main()char s=C+ program;char *ps1=computer;char *ps2,*ps3=s;ps2=mouse;couts ps1 ps2 ps3endl; ps1+;ps2+=2;ps3+=4;couts+4 ps1 ps2 ps3endl;cout*s *ps1 *ps2 *ps3endl; ps1=s;21.如果輸入的數據是24和18，則下列程序的輸出結果

13、是什么？#include int fun1(int c,int d)int r;r=c%d; while(r!=0) c=d;d=r; r=c%d;return d;void main()int m,n,e,d; coutmn;e=fun1(m,n); d=m*n/e;couteendl;coutdendl;22.#include void main()int a34=1,2,3,4,3,4,5,6,5,6,7,8;int b43,i,j; for(i=0;i3;i+)for(j=0;j4;j+) coutaij ;coutendl;for(i=0;i4;i+)for(j=0;j3;j+) b

14、ij=aji;for(i=0;i4;i+) for(j=0;j3;j+) coutbij ;25.coutendl;23.#include #include void main()const int m=5;int amm;int i,j;for(i=0;im;i+)ai0=1;aii=1; for(j=1;ji;j+) aij=ai-1j-1+ai-1j;for(i=0;im;i+)for(int k=0;k30-2*i;k+) cout ;for(j=0;j=i;j+) coutsetw(5)aij; coutendl;24.#include void main()char s30=com

15、puter,mouse,key; int i=0,k=0;coutsendl; while(si!=0)if(si=m)k+;i+;couti=iendl; coutk=kendl;#include #include struct studentchar num5;char name10;char sex;int age;float mathscore;void main()struct student st10=001,Wangping,f,19,84,002,Zhaomin,m,20,64,003,Wanghong,f,18,54,004,Lilei,m,19,92,005,Liumin,

16、m,19,75;int i,k=0;float average=0;for(i=0;i5;i+)average+=sti.mathscore;average/=10;coutaverage=averageendl;for(i=0;i5;i+)if(sti.mathscore60)k+;coutsti.num sti.sex;cout sti.age sti.mathscoreendl;coutkendl;#include void main()int b34=23,38,16,12,56,89,66,34,58,12,90,100;int i,j,m=3,n=4;for(i=

17、0;im;i+) for(j=0;jn;j+)cout*(*(b+i)+j) ;coutendl;for(i=0;i20;i+) cout-;coutendl;for(i=0;i=00;j-)cout*(bi+j) ;26.coutendl;for(i=0;i20;i+) cout-;cout=0;i-) for(j=0;jn;j+) coutbij ; coutendl;27.#include void main()int a=12,22,32,42,52,62,72,82,92,102;int i, m=5;int *p=a;for(i=0;im;i+)cout*p+ ;cout=0;i-

18、)coutpi ;coutendl;28.#include void main()int b24=12,36,62,14,56,98,74,63;int (*p)4=b;int i,j;for(i=0;i2;i+)for(j=0;j4;j+)cout*(*(p+i)+j) ; coutendl;for(i=0;i20;i+) cout-;coutendl;for(i=0;i=0;j-) coutpij ; coutendl;29.#include #include void main() int func(int a,int b,char op); int (*fptr)(int a,int

19、b,char op); fptr=func;coutfunc(3,5,+)endl;coutfptr(3,5,*)endl;int func(int a,int b,char op)switch(op)case +:coutaopb=;return a+b;break;coutaopb=;return a-b;break;coutaopb=;return a*b;break;coutOperator error!endl; return 0;30.#include struct student char *num;char *name; int age;void main()int *ip;f

20、loat *fp;char *cp; struct student *stp; fp=new float(32.6); cp=new char; *cp=A; ip=newint10; for(int i=0;inum=12;case -:default:stp-name=Li;stp-age=18;cout*fp *cp endl;coutnum=num name=name age=ageendl;for(i=0;i10;i+)coutipi ;coutendl;delete cp;delete fp;delete ip;delete stp;.#include class Pointpub

21、lic:Point(int xx=0,int yy=0)X=xx; Y=yy;cout構造函數被調用endl;Point(Point& p);int GetX( ) return X;int GetY( ) return Y;private:int X,Y;Point:Point (Point& p)X=p.X;Y=p.Y;cout拷貝構造函數被調用endl;Point fun2( ) Point A(1,2);return A;void fun1(Point p) coutp.GetX( )endl;void main( ) Point A(1,2);fun1(A);Point B(A);coutB.GetX( )endl;B=fun2();coutB.GetX( )endl;#include #include class Pointpublic:Point(int xx=0, int yy=0)X=xx;Y=yy;cout構造函數被調用endl;Point(Point &p);int GetX() return X;i