信號與系統Chapter 8Answers (1)_第1頁
信號與系統Chapter 8Answers (1)_第2頁
信號與系統Chapter 8Answers (1)_第3頁
信號與系統Chapter 8Answers (1)_第4頁
信號與系統Chapter 8Answers (1)_第5頁
已閱讀5頁,還剩3頁未讀 繼續免費閱讀

下載本文檔

版權說明:本文檔由用戶提供并上傳,收益歸屬內容提供方,若內容存在侵權,請進行舉報或認領

文檔簡介

1、Chapter 99.2Solution: (a). According to eq.(9.3), we will get ROC:Res>-5 (b). , Res<-5If then its obviously that A=-1, , Res<-5.9.5 Solution: (a).1, 1it has a zero in the finite s-plane, that is And because the order of the denominator exceeds the order of the numerator by 1 X(s) has 1 zero

2、 at infinity. (b).0, 1it has no zero in the finite s-plane.And because the order of the denominator exceeds the order of the numerator by 1 X(s) has 1 zero at infinity. (c).1, 0it has a zero in the finite s-plane, that is And because the order of the denominator equals to the order of the numerator

3、X(s) has no zero at infinity.9.7 Solution:There are 4 poles in the expression, but only 3 of them have different real part.The s-plane will be divided into 4 strips which parallel to the jw-axis and have no cut-across.There are 4 signals having the same Laplace transform expression.9.8 Solution: ROC

4、: R(x)+Re2 And x(t) have three possible ROC strips: g(t) have three possible ROC strips: IF Then the ROC of is (-1,1) is two sides.9.9 Solution: It is obtained from the partial-fractional expansion:,We can get the inverse Laplace transform from given formula and linear property. 9.10Solution: (a). I

5、ts lowpass. (b).Its bandpass. (c).Its highpass.9.13Solution: ,and The Laplace transform : and , From the scale property of Laplace transform, ,So ,From given ,We can determine : 9.21Solution: (a). , (b)., (i)., (f).,9.22Solution: (a). ,(b). ,(c) From the property of shifting in the time-domain and (

6、b),we can get , So , From the property of shifting in the s-domain,we can get ,and 9.28.Solution: (a).All possible ROCs: (b).Its obviouse to see:unstable &uncausalunstable &uncausalstable &uncausalunstable &causal9.31.Solution: (a). (b).1. The system is stable.ROC:(-1,2)2. The system

7、 is causal.ROC:3. The system is neither stable nor causalROC:9.32.Solution:from (1), for all tand x(t) is a eigen functionfrom (2) when , ,9.33. Solution:9.35. Solution:According to the block-diagram, we will know (a), Res>-1 (b) Its obviouse that this system is stable.9.37. Solution: (a) 9.45. Solution: ,-1<Res<2,Res<2, Res>-19.60. Solution:(a)Res: (b),the zeros of ,If , then . But couldnt reach infinit

溫馨提示

  • 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
  • 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯系上傳者。文件的所有權益歸上傳用戶所有。
  • 3. 本站RAR壓縮包中若帶圖紙,網頁內容里面會有圖紙預覽,若沒有圖紙預覽就沒有圖紙。
  • 4. 未經權益所有人同意不得將文件中的內容挪作商業或盈利用途。
  • 5. 人人文庫網僅提供信息存儲空間,僅對用戶上傳內容的表現方式做保護處理,對用戶上傳分享的文檔內容本身不做任何修改或編輯,并不能對任何下載內容負責。
  • 6. 下載文件中如有侵權或不適當內容,請與我們聯系,我們立即糾正。
  • 7. 本站不保證下載資源的準確性、安全性和完整性, 同時也不承擔用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。

評論

0/150

提交評論