電磁場與電磁波第15講邊界條件電感磁能_第1頁
電磁場與電磁波第15講邊界條件電感磁能_第2頁
電磁場與電磁波第15講邊界條件電感磁能_第3頁
電磁場與電磁波第15講邊界條件電感磁能_第4頁
電磁場與電磁波第15講邊界條件電感磁能_第5頁
已閱讀5頁,還剩28頁未讀 繼續免費閱讀

下載本文檔

版權說明:本文檔由用戶提供并上傳,收益歸屬內容提供方,若內容存在侵權,請進行舉報或認領

文檔簡介

11.TheMagneticDipole2.MagnetizationandEquivalentCurrentDensitiesReview23.MagneticFieldIntensityandRelativePermeabilityDifferentialformIntegralformPostulatesofMagnetostaticsinmagneticmaterial3MaintopicSteadyMagneticFields1.BoundaryConditionsforMagnetostaicFields2.InductancesandInductors3.MagneticEnergy41.BoundaryConditionsforMagnetostaicFields12B2H1B1H2an2Js5E2E1

2

1atwhacdban2hS

2

1an2D1D2s6(a)The

normal

componentsofthemagneticfluxdensityare

continuousacrossaninterface.For

linearisotropic

media,wehave(b)ThetangentialcomponentoftheHfieldisdiscontinuousacrossaninterfacewhereafreesurfacecurrentexistsThetangentialcomponentofHiscontinuous(連續)acrosstheboundaryofalmostallphysicalmedia;itisdiscontinuous(不連續)onlywhenaninterfacewithanidealperfectconductor(理想導體)orasuperconductor(超導體)isassumed.7Example1.Aloopmagneticcorewithagapiscloselywoundbyacoilwith

N

turns,asshowninthefigure.Whenthecoilcarriesacurrent

I,andtheleakage

magneticfluxoutsidethecoilis

neglected,findthemagneticfluxdensityandthemagneticfieldintensityinthecoreandthegap.Solution:Sincetheleakagemagneticfluxisneglected,thedirectionofthemagneticfluxdensityisaroundthecircle,anditisperpendiculartotheendfacesofthegap.Fromtheboundarycondition,weknowthatthemagneticfluxdensity

Bg

inthegapisequalto

Bf

inthecore,i.e.

8

Since

r0>>a

,themagneticfieldinthecorecanbeconsideredtobeuniform.UsingAmpere’scircuitallawinmedia,andtakingthecircleofradius

r0

astheintegralpath,thenwehave

Considering,wehave

ThenInthegapInthecore9

在線性媒質中,單個閉合回路電流產生的磁感應強度與回路電流I成正比,因此穿過回路的磁通也與回路電流

I成正比。式中L

稱為回路的電感,單位為H

(亨利)。由該定義可見,電感又可理解為與單位電流交鏈的磁通鏈。

單個回路的電感僅與回路的形狀及尺寸有關,與回路中電流無關。

與回路電流I交鏈的磁通稱為回路電流I的磁通鏈,以

表示,令與I

的比值為L,即應注意,磁通鏈與磁通不同,磁通鏈是指與某電流交鏈的磁通。2.InductancesandInductors10

若交鏈N次,則磁通鏈增加N倍;若部分交鏈,則必須給予適當的折扣。因此,與N匝回路電流I交鏈的磁通鏈為

=N。那么,由N

匝回路組成的線圈的電感為

與回路電流I1交鏈的磁通鏈是由兩部分磁通形成的,其一是I1本身產生的磁通形成的磁通鏈11

,另一是電流I2在回路l1中產生的磁通形成的磁通鏈12

。dl10zyxdl2l2l1I2I1r2-r1r2r1那么,與電流l1交鏈的磁通鏈1為11Mutualflux12(互磁通)Faraday’slawofelectromagneticinductionBiot-Savartlawwheretheproportionalityconstant

L12

iscalledthe

mutualinductance(互感)betweenloopsC1andC2,withtheunithenry(H).IncaseC2

hasN2turns,thefluxlinkage

12(磁鏈數)dueto

1212Themutualinductance(互感)betweentwocircuitsisthenthemagneticfluxlinkage(磁鏈數)withonecircuitperunitcurrent(單位電流)intheother.Itapplyonlytolinearmedia(線性媒質).AmoregeneraldefinitionforL12

isSomeofthemagneticfluxproducedbyI1linksonlywithC1itself,andnotwithC2.thetotalfluxlinkage(磁鏈數)

withC1

causedbyI1isNeumannformula13Theself-inductance(自感)ofloopC1

isdefinedasthemagneticfluxlinkage

(磁鏈數)

perunitcurrent(單位電流)intheloopitself.Thatis,foralinearmedium(線性媒質).IngeneraldefinitionforL11

isTheself-inductance(自感)ofalooporcircuitdependsonthegeometricalshape(幾何形狀)andthephysicalarrangement(實際排列)oftheconductorconstitutingthelooporcircuit,aswellasonthepermeabilityofthemedium(媒質的導磁率).Withalinearmedium,self-inductancedoesnotdependonthecurrentinthelooporcircuit.14Aconductorarrangedinanappropriatesshape(suchasaconductingwirewoundasacoil)tosupplyacertainamountofself-inductance(自感)

iscalledaninductor(電感器).Justasacapacitorcanstoreelectricenergy,andinductorcanstoragemagneticenergy.Theprocedurefordeterminingtheself-inductanceofaninductorisasfollows:1.Chooseanappropriatecoordinatesystemforthegivengeometry.2.AssumeacurrentI

intheconductingwire.3.FindBfromIbyAmpere’scircuitallaw

ifsymmetryexists;ifnot,Biot-Savartlawmustbeused.4.Findthefluxlinkingwitheachturn,,fromBbyintegration:whereSistheareaoverwhichBexistsandlinkswiththeassumedcurrent.5.Findthefluxlinkage

bymultiplyingbythenumberofturns.

6.FindLbytakingtheratioL=/I.15EXAMPLE6-14P26916Example.

Calculatethemutualinductance(互感)betweenaninfinitelylongstraightlineandarectangularcoil.Thelineandthecoilareatthesameplane,andinvacuum.abdrrD0I1I2zS2Solution:Selectcylindricalcoordinatesystem,andlettheinfinitelylongstraightlinetobeatthe

z-axis.Themagneticfluxdensityproducedbycurrent

I1

isthen

Themagneticfluxlinkage

12

withcurrent

I2

bycurrent

I1

is17Wehave

Iftheflowingdirectionofthecurrent

I2

iscounter

clockwise,thenthe

B1

and

dS

areopposite,and

L12<0.abdrrD0I1I2zS2

Iftheflowingdirectionofthecurrent

I2

isclockwise,dS

and

B1

havethesamedirection.Then18例題:求無限長導線與三角形回路之間的互感I1rdrzx0193.MagneticEnergy

If

animpressedsource(外源)isappliedtoacircuit(回路),acurrentwillbegeneratedinthecircuit.Intheprocessofestablishingthecurrent,the

reactionmagneticflux(感應磁通)inthecircuitwillresist(阻止)theincrementofthecurrent.

Assumethecurrentisincreased

veryslowly(非常慢)

sothat

radiationloss

canbeneglected,

allenergy

providedbytheimpressedsourcewillbestored(儲存)inthe

magneticfield

aroundthecircuit.

Basedontheworkdonebythe

impressedsource,theenergystoredinthemagneticfieldcanbecalculated.

Inordertoovercomethebackelectromotiveforceduetothereactionmagneticfluxandtomaintainthecurrent,

theimpressedsourcehastodowork(做功).20Considerasingleclosedloop(閉合回路)withaself-inductanceL1inwhichthecurrentisinitiallyzerotoI1.Fromphysicsweknowthatanemf(電動勢)willbeinducedintheloopthatopposesthecurrentchange.Anamountofworkmustbedonetoovercomethisinducedemf(感應電動勢).Letv1=L1di1/dtbethevoltage(電壓)acrosstheinductance.TheworkrequiredisSinceL1=1/I1forlinearmedia(線性媒質),theequqtioncanbewrittenwhichisstoredasmagneticenergy(磁能).NowconsidertwoclosedloopsC1andC2carryingcurrentsi1andi2,respectively.ThetotalamountofworkdoneinrasingthecurrentsinloopsC1andC2fromzerotoI1andI2,respcetively,is21whichisstoredasmagneticenergy.WhereW21isGeneralizingthisresulttoasystemofNloops(N個回路)carryingcurrentsI1,I2,…In,weobtainWhichistheenergystoredinthemagneticfield.ForacurrentIflowinginasingleinductor(單個電感器)withinductanceL,thestoredmagneticenergyis22ItisoftendesirabletoexpressthemagneticenergyintermsoffieldquantitiesBandH.WehaveNotingthatH=B/,wecan

溫馨提示

  • 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
  • 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯系上傳者。文件的所有權益歸上傳用戶所有。
  • 3. 本站RAR壓縮包中若帶圖紙,網頁內容里面會有圖紙預覽,若沒有圖紙預覽就沒有圖紙。
  • 4. 未經權益所有人同意不得將文件中的內容挪作商業或盈利用途。
  • 5. 人人文庫網僅提供信息存儲空間,僅對用戶上傳內容的表現方式做保護處理,對用戶上傳分享的文檔內容本身不做任何修改或編輯,并不能對任何下載內容負責。
  • 6. 下載文件中如有侵權或不適當內容,請與我們聯系,我們立即糾正。
  • 7. 本站不保證下載資源的準確性、安全性和完整性, 同時也不承擔用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。

評論

0/150

提交評論