實用標準文檔用ANSYS建立鋼筋混凝土梁模型問題描述：鋼筋混凝土梁在受到中間位移荷載的條件下的變形以及個組成部分的應力情況。P=5mm位移L=2000mm

H=300mmB=150mm圖1鋼筋混凝土結構尺寸圖一、用合并節點的方法模擬鋼筋混凝土梁1．用solid65 號單元以及beam188單元時材料特性鋼材的應力應變關系混凝土的彈性模量采用線彈性文案大全實用標準文檔建立鋼筋線對鋼筋線劃分網格后形成鋼筋單元文案大全實用標準文檔建立混凝土單元合并單元節點后施加約束以及位移載荷文案大全實用標準文檔進入求解器進行求解鋼筋單元的受力云圖混凝土的應力云圖文案大全實用標準文檔混凝土開裂2使用單元solid45 號單元 與beam188鋼筋的應力應變關系不變，而混凝土應力應變關系為：混凝土單元文案大全實用標準文檔鋼筋單元力與位移曲線文案大全實用標準文檔tbpt,,0.002795333,2.48e1合并節點時的命令流:tbpt,,0.0031972,2.40e1tbpt,,0.003599067,2.32e1tbpt,,0.0038,2.28e1finitb,conc,1,1,9tbdata,,0.4,1,3,-1/clear,nostart!縱向受拉鋼筋/config,nres,5000mp,ex,2,2e5/prep7mp,prxy,2,0.3/title,rc-beamtb,bkin,2,1,2,1b=150tbdata,,350h=300!橫向箍筋，受壓鋼筋材料屬性a=30mp,ex,3,2e5l=2000mp,prxy,3,0.25fcu=40tb,bkin,3,1,2,1ec=2.85e4tbdata,,200displacement=10!生成鋼筋線!定義單元類型k,,et,1,solid45k,,bet,2,beam188kgen,2,1,2,,,het,3,plane42k,,a,a!定義截面類型k,,b-a,asectype,1,beam,csolid,,0kgen,2,5,6,,,h-2*asecoffset,centkgen,21,5,8,,,,-100secdata,8,0,0,0,0,0,0,0,0,0*do,i,5,84,1sectype,2,beam,csolid,,0l,i,i+4secoffset,cent*enddosecdata,4,0,0,0,0,0,0,0,0,0*do,i,5,85,4!定義材料屬性，混凝土材料屬性l,i,i+1mp,ex,1,ecl,i,i+2mp,prxy,1,0.2*enddotb,kinh,1,,16*do,i,8,88,4tbpt,,0.000179067,5.10l,i,i-1tbpt,,0.000358133,9.67l,i,i-2tbpt,,0.0005372,1.37e1*enddotbpt,,0.000716267,1.72e1!受拉鋼筋tbpt,,0.000895333,2.01e1lsel,s,loc,y,atbpt,,0.0010744,2.26e1lsel,r,loc,x,atbpt,,0.001253467,2.44e1lsel,a,loc,x,b-atbpt,,0.001432533,2.58e1lsel,r,loc,y,atbpt,,0.0016116,2.66e1cm,longitudinal,linetbpt,,0.001790667,2.69e1type,2tbpt,,0.0019916,2.65e1mat,2tbpt,,0.002393467,2.57e1文案大全實用標準文檔secnum,1 d,all,uylesize,all,50 d,all,uxlmesh,all !施加外部荷載alls /solucmsel,u,longitudinal nsel,allcm,hoopingreinforcement,line nsel,s,loc,y,h!箍筋，受壓鋼筋 nsel,r,loc,z,-1000type,2 d,all,uy,-displacementmat,2 allssecnum,2 !求解lesize,all,50 nlgeom,onlmesh,all nsubst,50/eshape,1 outres,all,all!將鋼筋節點建為一個集合 neqit,50cm,steel,node pred,on!生成面單元，以便拉伸成體單元 cnvtol,f,,0.05,2,0.5a,1,2,4,3 allsellsel,s,loc,y,0 solvelsel,a,loc,y,h finishlesize,all,,,8 /post1lsel,all allsellsel,s,loc,x,0 /device,vector,1lsel,a,loc,x,b !時間歷程后處理lesize,all,,,10 /post26type,3 nsel,s,loc,z,-l/2amesh,all *get,Nmin,node,0,num,min!拉伸成混凝土單元 nsol,2,nmin,u,ytype,1 prod,3,2,,,,,,-1real,3 nsel,s,loc,y,0mat,1 nsel,r,loc,z,0extopt,esize,20 *get,Nnum,node,0,countextopt,aclear,1 *get,Nmin,node,0,num,minvext,all,,,,,-l n0=Nminalls rforce,5,Nmin,f,y!合并節點 *do,i,2,ndinqr(1,13)nummrg,all ni=ndnext(n0)numcmp,all rforce,6,ni,f,y!邊界條件約束 add,5,5,6nsel,s,loc,y,0 n0=ninsel,r,loc,z,0 *enddod,all,uy prod,7,5,,,,,,1/1000d,all,ux /axlab,x,uynsel,s,loc,y,0 /axlab,y,p(kn)nsel,r,loc,z,-l xvar,3文案大全實用標準文檔plvar,7二、用約束方程法模擬鋼筋混凝土梁1．用solid65 號單元以及beam188單元時混凝土以及鋼筋采用線彈性關系：建立鋼筋線對鋼筋線劃分網格后形成鋼筋單元文案大全實用標準文檔建立混凝土單元對鋼筋線節點以及混凝土節點之間建立約束方程文案大全實用標準文檔后施加約束以及位移載荷進入求解器進行求解；鋼筋單元的受力云圖混凝土的應力云圖文案大全實用標準文檔混凝土開裂2使用單元solid45 號單元 與beam188使用混凝土的本構關系曲線文案大全實用標準文檔鋼材的本構關系曲線鋼筋的vonmises應力文案大全實用標準文檔混凝土的應力用在solid45號單元下，用合并節點法、約束方程法建立模中鋼筋與混凝土之間的關系的時候的一個力與位移全程曲線的比較。12010080合并節點60約束方程402000 2 4 6 8 10 12文案大全實用標準文檔約束方程法命令流:fini tbpt,,0.003599067,2.32e1/clear,nostart tbpt,,0.0038,2.28e1/config,nres,5000 !tb,conc,1,1,9/prep7 !tbdata,,0.4,1,3,-1/title,rc-beam !縱向受拉鋼筋b=150 mp,ex,2,2e5h=300 mp,prxy,2,0.3a=30 tb,bkin,2,1,2,1l=2000 tbdata,,350fcu=40 !橫向箍筋，受壓鋼筋材料屬性ec=2.85e4 mp,ex,3,2e5displacement=5 mp,prxy,3,0.25!定義單元類型 tb,bkin,3,1,2,1et,1,solid65 tbdata,,200et,2,beam188 !生成鋼筋線et,3,plane42 k,,!定義截面類型 k,,bsectype,1,beam,csolid,,0 kgen,2,1,2,,,hsecoffset,cent k,,a,asecdata,8,0,0,0,0,0,0,0,0,0 k,,b-a,asectype,2,beam,csolid,,0 kgen,2,5,6,,,h-2*asecoffset,cent kgen,21,5,8,,,,-100secdata,4,0,0,0,0,0,0,0,0,0 *do,i,5,84,1!定義材料屬性，混凝土材料屬性 l,i,i+4mp,ex,1,ec *enddomp,prxy,1,0.2 *do,i,9,81,4tb,kinh,1,,16 l,i,i+1tbpt,,0.000179067,5.10 l,i,i+2tbpt,,0.000358133,9.67 *enddotbpt,,0.0005372,1.37e1 *do,i,12,84,4tbpt,,0.000716267,1.72e1 l,i,i-1tbpt,,0.000895333,2.01e1 l,i,i-2tbpt,,0.0010744,2.26e1 *enddotbpt,,0.001253467,2.44e1 !受拉鋼筋tbpt,,0.001432533,2.58e1 lsel,s,loc,y,atbpt,,0.0016116,2.66e1 lsel,r,loc,x,atbpt,,0.001790667,2.69e1 lsel,a,loc,x,b-atbpt,,0.0019916,2.65e1 lsel,r,loc,y,atbpt,,0.002393467,2.57e1 cm,longitudinal,linetbpt,,0.002795333,2.48e1 type,2tbpt,,0.0031972,2.40e1 mat,2文案大全實用標準文檔secnum,1 d,all,uxlesize,all,50 nsel,s,loc,y,0lmesh,all nsel,r,loc,z,-lalls d,all,uycmsel,u,longitudinal d,all,uxcm,hoopingreinforcement,line !施加外部荷載!箍筋，受壓鋼筋 /solutype,2 nsel,allmat,2 nsel,s,loc,y,hsecnum,2 nsel,r,loc,z,-1000lesize,all,50 d,all,uy,-displacementlmesh,all alls/eshape,1 !求解!將鋼筋節點建為一個集合 nlgeom,oncm,steel,node nsubst,200!生成面單元，以便拉伸成體單元 outres,all,alla,1,2,4,3 neqit,100lsel,s,loc,y,0 pred,onlsel,a,loc,y,h cnvtol,f,,0.05,2,0.5lesize,all,,,10 allsellsel,all solvelsel,s,loc,x,0 finishlsel,a,loc,x,b /post1lesize,all,,,20 allseltype,3 plcrack,0,1amesh,all plcrack,0,2!拉伸成混凝土單元 !時間歷程后處理type,1 /post26real,3 nsel,s,loc,z,-l/2mat,1 *get,Nmin,node,0,num,minextopt,esize,30 nsol,2,nmin,u,yextopt,aclear,1 prod,3,2,,,,,,-1vext,all,,,,,-l nsel,s,loc,y,0alls nsel,r,loc,z,0!建立約束方程 *get,Nnum,node,0,countcmsel,s,hoopingreinforcement *get,Nmin,node,0,num,mincmsel,a,