R122221R122221學(xué)年山東省濰坊高一（上）中數(shù)學(xué)試一單選題本題小，小分共分．每題出四選中只一是合目求．{2x0}A1ABCA{x2}DabAa2

abB+2CDAyB

yCy

yx+1Dy

yxRx2nN*ARx2N*

BRx2nN*CxRxN*

DxRx

N*yax++aaA1B1

DxRf0Af12Cff

Bff2Df0Er

2

RPrR

21211ArRR

Br

CR

2

DR+RryfxPbyx+aAfx+1Bfxx

32

Cfxafx+Dfxx2x+5f1二多選題本題小，小5分共20分在小給的個項中有項合目求．部對得5分有錯得分，部選的分b0a1Aa2

+b2

B

CD410xm3x+AmBm1CDm11fAfyBfx2+CfxDxx12A*CCB|{0}B{xx2+ax+20}A*

RRRRA

B0CD三填題本題4小題每題5分共20分．答填答卡相位．13{2}{212}M143152xxx0+16數(shù)

.在R的數(shù)實a圍四解題本題6小題共70分解應(yīng)出字明證過程演步．171x+x

2

18A{3}{2

2+20}1a1AA2___①A②B?③AxB200m

/m/m1yxm3

11120[3]1f2[3]xx

x+x0f021fx22+3x+53]1a1fx2fx[14a22fax2+bx+1aFx1ffx0Fx2x[2gfkx3mn0m+0afxFm+

RR參考答案一單選題本題小，小分共分．每題出四選中只一是合目求．{2x0}A1ABCA{x2}DA{x

2x0}{x02}abAa2

abB+2CDAa0a0a2

0abbabb+bBC0b0D，b0D

DA

yxB

y

Cy

yx+1Dy

yxAyx

Ry

xxRyyx[0+Cy00+yx+1RDRyxRDRx2nN*ARx2N*CxRxN*

BRx2nN*DxRxnN*xRxC

nN*yax++aaA1B1

DAD0x0

122221212222121122a0x0

Cxa2a1

1D，a0xa2aa1xRf0Af12Cff

Bff2Df0xRffx01fff12CEr

2

RPrRArRR

Br

CR

2

DR+RrPUI

2222222PI

UU

RyfxPbyx+aAfx+1Bfxxx1Cfxafx+Dfxx

xfPbyfxabyf+fx+fx+fxa+fxafx2+1fx++fx+x+1+2++120fxx

3xx

xabfx+1fx+1+1

x+1x2+142BCfaxf2xx+afatxx+afxfxff+fx+h+hf2hf

xhfxfxx+8f12+4+8fx1fxxDC二多選題本題小，小5分共20分在小給的個項中有項合目求．部對得5分有錯得分，部選的分b0a1Aa2

+b2

B

CD4ab+1A

+b2

aAB

abBCD

4D10xm3x+AmBm1CDmx2+m3x+03m10m3mm0m1B

m10m+901mC3xx

+m3+x2+30D11fAfyBfx2+CfxRDx2fxfBfx0DAffx

{x2}xxxAx220x

x+fxx[02Cfx0D，2x

fxfxf

fxf0x2xDAD12A*CCB|{0}B{xx2+ax+20}A*A

B0CDCA2A*132

xx+032+32ax+20

aA{12}CA2A*1CB132+3+ax+2xx2+ax+20axxx2ax+22+30x00a0B{0}Ba0①x+0002

a2a

B{02{02

}}B3②x2++2aa3B{012}a3{02}B3ABD

三填題本題4小題每題5分共20分．答填答卡相位．13{2}{212}M1{m}{22}mm1{2}{22}m2mm1143

ff5ffx

fff72152xxx0+

b3xgb++1x+fxgx0+xx

++x++1x+++++1

x

x0fxxb

x0+fg

+1x0+fxg164]

Ra

[2據(jù)x

x2|數(shù)2

x[2+

RR

R4a[4]四解題本題6小題共70分解應(yīng)出字明證過程演步．171x+x

2

x+

3+x

xx

2x1x+

3

x1+29x+xx+1x

x49x

+2xx2

x

+245xx

218A{3}{2

2+20}1a1AA

RRRRRRRR2___①A②B?③AxBB2{4|3}{x7}B{x3}A{17}BA{x1}

2x30}{2①ABB{x

2ax+a20}{a2a5a[5]②A{+a240}{axa{x7}a5a[5]③xB{22axa20}{2a5a[5]200m

/m/m1yxm3

111xmy21xm

mxx4yy18400+400+

4200[200x

4]2x

20

x

x

2.9720[3]

x+x0f1f2[3]xx11

2[3]fxfx

fx+f0

11212111121211221212112f09f2[3xx[33xx3

03x3

x0xx0fxfxffxx[3[x21fx22+3x+53]

01a1fx2fx[14a1a1xx25+52

x[0

xfxxf2xx2+3axx[0x

afxf3814xaxf014a22fax2+bx+1aFx1ffx0Fx2x[2gfkx3mn0m+0afxFm+1