一、單項選擇題：本題包含7小題，每小題4分，共28分。題號1234567選項DDABCBB二、多項選擇題：本題包含3小題，每小題6分，共18分。題號89選項ACACABC三、實驗題：共16分。（1）10（1分）（2）50（2分）（3）不變（1分）越小（1分）（4）偏小（2分）12.（9分）（1）R1（1分）（2）PTC（1分）NTC（1分）（3）變小（2分）（4）2.12（1分）1.48（1分）偏大（2分）四、計算題：共38分。13.（8分）（1）光源1到亮紋的距離為r1，光源2到亮紋的距離為r2，光源1到r2的距離與兩個光源:距離的夾角為θ,若亮紋到光屏中心的距離為xr2-n1=2asino··········································································（1分）axlsin9····················································································（1分）2a····················································································（1分）····················································································（1分）（2）五條連續(xù)亮紋間距為x=6cm，因為5條亮紋間有4個間距，相鄰亮紋間距···················································································（1分）14.（14分）（1）M剛到達C點尚未與N發(fā)生碰撞時，對BC管道的壓力恰好為0，此時M只受重力···················································································（1分）vc=gRM由A到C，根據(jù)機械能守恒定律h=R（2）M與N發(fā)生彈性正碰，碰撞過程中動量守恒、機械能守恒。設(shè)碰撞后M的速度為，N的速度為vmvc=mu'c+mv·······································································（1分）·································································（1分）···················································································（1分）（3）根據(jù)牛頓第二定律2對于P:································································（1分）對于Q:4ymg+umg=man···················································（1分）對于P:··························································（1分）對于Q:ox=0-awt=v死-5ugt········································（1分）······················································································（1分）對于N:·····························································（1分）對于Q:········································································（1分）P與N右端的最大距離··············································（1分）15.（16分）（1）設(shè)正離子經(jīng)bc間電壓加速后從d處噴出時的速度為v,qu=m2····························································（2分）選取研究對象Am=n-OAt.mr2.m································（2）根據(jù)動量定理，N車對離子的作用力為，以初速度方向為正FAt=Am·(-v)-AmvF=2F······························································（2分）F'=2F··································································（1分）（3）正離子在磁場中做勻速圓周運動，洛倫茲力提供向心力，軌道半徑R=2r3·······················