




版權說明:本文檔由用戶提供并上傳,收益歸屬內容提供方,若內容存在侵權,請進行舉報或認領
文檔簡介
目錄(Contents)TOC\o"1-3"1 練習簡介(Briefdescriptionofthee*ercises) 12 實用工具(Aids) 23 練習(E*ercises) 33.1 構造設計形式為M的減速電機(GearedmotordesignM)33.2 構造設計開工為N的減速電機(GearedmotordesignN)43.3 制動單元練習1(Brakingunit1)53.4 制動單元練習2(Brakingunit2)63.5 傳動軸(Spindle)74 練習答案(Solutions)84.1 構造設計形式為M的減速電機(GearedmotordesignM)84.2 構造設計形式為N的減速電機(GearedmotordesignN)104.3 制動單元練習1(Brakingunit1)124.4 制動單元練習2(Brakingunit2)144.5傳動軸(Spindle)15練習簡介(Briefdescriptionofthee*ercises)主題(Topic)容(Contents)難度(Grade)傳動軸驅動Spindledrive往復傳動軸(Cyclicspindledrive)需選擇:電機、變頻器、制動單元(searched:Motor,inverter,brakingunit)高(High)制動單元(Brakingunit)加速傳動(Accelerationdrive)一般(Normal)制動單元(Brakingunit)提升,電阻混聯(Hoist,resistornetwork)高(High)直流母線(DCbus)直流母線運行實例(E*amplesofDCbusoperation)一般(Normal)減速電機(Gearedmotor)設計形式為M的Lenze減速電機的選型(CatalogueselectionofaLenzegearedmotorinM-design)一般(Normal)減速電機(Gearedmotor)設計形式為N的Lenze減速電機的選型(CatalogueselectionofagearedmotorinN-design)一般(Normal)橫切機(Crosscutter)卷曲設備(Winder)提升設備(Liftdrive)傳輸設備(Travellingdrive)實用工具(Aids)計算器(Pocketcalculator)Lenze選型手冊(Lenzecatalogues)Lenze公式集(Lenzeformulacollection)練習(E*ercises)3.1設計形式為M的Lenze減速電機的選型(GearedmotordesignM)減速電機按S2方式進展傳動(運行時間=10min),此時,可采用常規運行方式。[AgearedmotoristodrivealoadinS2operation(operatingtime=10min).Inthiscase,aregularoperationisgiven.]具體數據(Detaileddata):轉矩(Processtorque): M2=580Nm速度(Processspeed): n2=100rev/min主電壓(Mainsvoltage): VMains=400V主電源頻率(Mainsfrequency): fMains=50Hz運行時間(Operatingtime/day): 8h所需部件(Searchedponents):Lenze異步電機(Lenzeasynchronousmotor)GST減速器(Gearbo*GST)3.2設計形式為N的Lenze減速電機的選型(GearedmotordesignN)減速電機按S2方式進展傳動(運行時間=10min),此時,可采用常規運行方式。[AgearedmotoristodrivealoadinS2operation(operatingtime=10min).Inthiscase,aregularoperationisgiven.]具體數據(Detaileddata):轉矩(Processtorque): M2=580Nm速度(Processspeed): n2=100rev/min主電壓(Mainsvoltage): VMains=400V主電源頻率(Mainsfrequency): fMains=50Hz運行時間(Operatingtime/day): 8h所需部件(Searchedponents):Lenze異步電機(Lenzeasynchronousmotor)GST減速器(Gearbo*GST)注:N型減速器可用于IEC連接,作為規則連接,該型電機應為外置式。為便于計算,可選用Lenze電機。(Note:TypeNisdesignedformotorswithanIECconnection.Asarulethesearee*ternalmotors.Tomakecalculatingeasier,Lenzemotorscanbeusedforthiscalculation.)3.3制動單元1(Brakingunit1)Process:利用伺服控制對圓柱型固體進展加速及制動的驅動特性如上圖所示。(Asolidcylinderisacceleratedandbrakedbyaservodriveasshownintheabovecharacteristic.)具體數據(Detaileddata):圓柱體質量(Massofthecylinder): m=2kg圓柱體半徑(Radiusofthecylinder):r=0.25m摩擦轉矩(rictiontorque):MFriction=3Nm最大速度(Ma*.speed): n=2500rpm加速時間(Accelerationtime): t1=2s延遲時間(Delaytime): t3=1s靜止周期(Restperiod): t4=1s循環周期(Cycletime): T=7s電機成效(Efficiencyofthemotor): Motor=0.8電機轉動慣量(Momentofinertiaofthemotor): JMotor=10kgcm2變頻器功耗(Powerlossoftheinverter): PV=260W需選擇(Searchedponents):制動單元(Brakingunit,resistor)轉矩及功率曲線(Torqueandpowerprofile)3.4制動單元2(Brakingunit2)電機(Motor):兩臺37kW電機,忽略成效(平安預留)[2motorswith37kWefficiencyneglected(safetyreserve)]控制器(Controller): 兩臺EVF9200ES,忽略功耗(平安預留)[2piecesoftheEVF9330-ESpowerlossneglected(safetyreserve)]質量(Mass): m=130,000kg高度(Height): h=55m速度(Speed): v=3m/min接觸傾角(Nocontactbevelangle)=0°應用圍:(Application:Hoistwithoutcounter-weight.)需選擇(Searchedponents):制動單元,制動電阻(Brakingunit,resistor)3.5傳動軸(Spindle)應用(Application):傳動軸用于延固定軌跡傳送一剛體,此時,傳動往復路徑是一致的,剛體安裝在導軌上。(Thespindleistomoveamassofsteelaccordingtoaspecifiedprofile.Inthiscase,thereturntripisthesame.Themassismountedonrails.)具體數據(Detaileddata):材料質量(Materialmass): 1.5t前進距離(Forwardfeeddistance): 240mm傳動軸材料(Spindlematerial): 鋼(steel)傳動軸傾度(Spindlepitch): 10mm傳動軸摩擦直徑(Spindlefrictiondiameter): 28mm傳動軸類型(Spindletype): 球軸承(ballbearingspindle)傳動軸長度(Spindlelength): 900mm傳輸速度(Traversingspeed): 12m/min加速時間(Accelerationtime): 0.3sto0.5s延遲時間(Delaytime): 0.3sto0.5s靜止周期(Restperiod): 0.1s與導軌之前的摩擦系數(Frictioncoefficientoftherails):b=0.02需選擇(Searchedponents):異步電機(不帶減速器)[Asynchronousmotor(withoutgearbo*)]變頻器(矢量型)[Frequencyinverter(vector)]制動斬波器,制動電阻(Brakechopper,resistor0練習答案(Solutions)設計形式為M的Lenze減速電機的選型(GearedmotordesignM)求傳輸功率(Calculationoftheprocesspower) (STYLEREF1\n4.SEQGleichung\*ARABIC\n1)求kS2=1.4且Gearbo*,initial=0.95時所需的電機功率:(CalculationoftherequiredmotorpowerwithkS2=1.4andGearbo*,initial=0.95) (STYLEREF1\n4.SEQGleichung\*ARABIC\n2)根據主電源數據選擇電機電壓及頻率(Motorvoltageandmotorfrequencycorrespondtothemainsdata.)可選擇4極異步電機:112-32(A4-poleasynchronousmotorisselected:112-32.)電機型號(Motorsize)PNnrIrIA/IrV*frcosMrMstallMAJ[kW][min-1][A][A][V]Y/[Hz][%][Nm][Nm][NM][10-3kgm2]112-325.5144012.58.0-/4002)500.788936.5138.7105.922.8供電電壓:400V,連接方式:角接(Deltainterconnectionwith400V.)求減速器速比(Calculationofthesetpointgearbo*ratio): (STYLEREF1\n4.SEQGleichung\*ARABIC\n3)負載等級為I。(LoadclassIisdefined.)由于在S2方式下運行10分鐘,故每小時開關次數很少。(ThenumberofoperationsperhourisverysmallbecauseoftheS2operationof10minutes.)運行因子最大為0.9。(Thisleadstoanoperationfactorkofma*.0.9.)根據"G-motionconst"手冊中14.286.c=1.3查出iactual(SelectionofiactualintheG_Motionconstcatalogueof14.286.c=1.3.)此時(Inthiscase):ckGST07-2M假設所需傳遞的轉矩傳至電機側,則結果為Gearbo*=0.97(Iftherequestedprocesstorqueistransformedtothemotorside,theresultisasfollows:Gearbo*=0.97) (STYLEREF1\n4.SEQGleichung\*ARABIC\n4)可根據電機的運行值求出C。(Ccouldberecalculatedbasedontheoperatingpointofthemotor.) (STYLEREF1\n4.SEQGleichung\*ARABIC\n5)為校核啟動轉矩,必須將M2*作為MA,為獲得充足的加速裕量,必須確保在所額定值下都能啟動:(MA.Tocheckthestartingtorque,M2*hastobeparedtoMA.Startingisatanyrateensuredbecausesufficientaccelerationreservesareavailable.)S2方式下允許的電機轉矩為:(ThepermissibletorqueofthemotorforS2-operationis) (STYLEREF1\n4.SEQGleichung\*ARABIC\n6)電機不會過載。(Themotorisnotoverloaded.)設計形式為N的Lenze減速電機的選型(GearedmotordesignN)求傳輸功率(Calculationoftheprocesspower)(STYLEREF1\n4.SEQGleichung\*ARABIC\n7)求kS2=1.4且Gearbo*,initial=0.95時所需的電機功率:(CalculationoftherequiredmotorpowerwithkS2=1.4andGearbo*,initial=0.95) (STYLEREF1\n4.SEQGleichung\*ARABIC\n8)根據主電源數據選擇電機電壓及頻率(Motorvoltageandmotorfrequencycorrespondtothemainsdata.)可選擇4極異步電機:112-32(A4-poleasynchronousmotorisselected:112-32.)電機型號(Motorsize)PNnrIrIA/IrV*frcosMrMstallMAJ[kW][min-1][A][A][V]Y/[Hz][%][Nm][Nm][NM][10-3kgm2]112-325.5144012.58.0-/4002)500.788936.5138.7105.922.8供電電壓:400V,連接方式:角接(Deltainterconnectionwith400V.)求減速器速比(Calculationofthesetpointgearbo*ratio): (STYLEREF1\n4.SEQGleichung\*ARABIC\n9)負載等級為I。(LoadclassIisdefined.)由于在S2方式下運行10分鐘,故每小時開關次數很少。(ThenumberofoperationsperhourisverysmallbecauseoftheS2operationof10minutes.)運行因子最大為0.9。(Thisleadstoanoperationfactorkofma*.0.9.)在"G_Motionconst"手冊中查閱N型減速器數據,查出iactual。(SelectionofiactualintheG_MotionconstcataloguedesignN.)特性(Characteristics):M2permn1IEC連接(IEC-connection)iactual=14.286 GST07-2NM2perm=624NmM2*k假設所需傳遞的轉矩傳至電機側,則結果為Gearbo*=0.97(Iftherequestedprocesstorqueistransformedtothemotorside,theresultisasfollows:Gearbo*=0.97) (STYLEREF1\n4.SEQGleichung\*ARABIC\n10)為校核啟動轉矩,必須將M2*作為MA,為獲得充足的加速裕量,必須確保在所有額定值下都能啟動:(MA.Tocheckthestartingtorque,M2*hastobeparedtoMA.Startingisatanyrateensuredbecausesufficientaccelerationreservesareavailable.)S2方式下允許的電機轉矩為:(ThepermissibletorqueofthemotorforS2-operationis) (STYLEREF1\n4.11)電機不會過載。(Themotorisnotoverloaded.)制動單元1(Brakingunit1)求轉動慣量(Calculationofthemomentofinertia)下式適于圓柱固體轉動慣量的計算(Forasolidcylinderthefollowingformulaapplies): (STYLEREF1\n4.SEQGleichung\*ARABIC\n11)從而可得(Asaresultthetotalinertiais) (STYLEREF1\n4.SEQGleichung\*ARABIC\n12) (STYLEREF1\n4.SEQGleichung\*ARABIC\n13)運動學分析:(Kinematics)延遲Delay: (STYLEREF1\n4.SEQGleichung\*ARABIC\n14)制動時,動態傳輸轉矩按下式計算:(Whenbraking,thedynamicprocesstorqueiscalculatedasfollows) (STYLEREF1\n4.SEQGleichung\*ARABIC\n15)總制動轉矩(Thetotalbrakingtorque) (STYLEREF1\n4.SEQGleichung\*ARABIC\n16)相應的制動功率峰值:(Thecorrespondingpeakbrakepoweroftheprocess) (STYLEREF1\n4.SEQGleichung\*ARABIC\n17)直流母線上的制動功率:(ThepeakbrakepowerattheDCbusis) (STYLEREF1\n4.SEQGleichung\*ARABIC\n18)連續制動功率:(Calculationofthecontinuousbrakingpower) (STYLEREF1\n4.SEQGleichung\*ARABIC\n19)由于制動功率是連續的,因此不允許使用制動模塊,必須使用制動斬波器。(Duetothecontinuousbrakingpower,itisnotpossibletouseabrakingmodule.Thebrakingchopper9352hastobeused.)制動電阻最大值按下式計算:(Thema*imumbrakingresistoriscalculatedasfollows) (STYLEREF1\n4.SEQGleichung\*ARABIC\n20)制動電阻最小值(Calculationoftheminimumbrakingresistor) (STYLEREF1\n4.SEQGleichung\*ARABIC\n21)求制動電阻熱容量:(Calculationoftherequiredthermalcapacitanceoftheresistor) (STYLEREF1\n4.SEQGleichung\*ARABIC\n22)制動電阻值必須介于RBrake,min和RBrake,ma*之間,且其熱容量應大于所需制動能量,但是,制動電阻必須滿足連續制動及制動功率峰值要求。(TheresistorvaluemustbebetweenRBrake,minandRBrake,ma*andhaveahigherthermalcapacitancethanthebrakingenergyrequired.Moreover,itmustbeabletohandlethecontinuousandpeakpower.)結論:制動電阻值RBrake=180(Asaresult,thefollowingresistorcanbeused:RBrake=180)制動單元2(Brakingunit2)驅動所需時間:(Timerequiredforonedrive)制動運行時,發電模式產生的功率為:(Whenmovingdownwardsagenerator-modepowerof)此時,制動功率持續上升,必須使用多臺控制斬波器。(Thebrakingpowerarisescontinuouslyandhastobedissipatedbyseveralbrakingchoppers.)9352制動斬波器可處理19kW連續制動功率,這意味著需4臺9352。[Thebrakingchopper9352canhandle19kWcontinuously.Thismeansthatatotalof4brakingchoppersareneeded.Eachchopperhastodissipateaquarter(appro*.16
kW)ofthetotalpower.]每臺制動斬波器配備的制動電阻值為:(Thecorrespondingbrakingresistorperchopperiscalculatedasfollows)又因為電阻的阻值應在18
到32.85
之間,同時,制動電阻應可消耗16kW連續制動功率。(Theminimumbrakingresistoris18.Theselectedresistorvalueshouldbebetween18
and32.85
.Moreover,thebrakingresistormustbeabletohandle16kWcontinuously.)可行方案為將6支18
電阻按下列圖混聯。(Apossi‰blesolutionisagroupconnectionofatotalofsi*18
resistors.)總制動電阻值為:〔Inthiscase,twotimes3resistorshavetobeconnectedinseriesandbothseriesconnectionshavetobesetinparallel.Thisresultsinthefollowingresistorvalue〕這樣,每支制動電阻制動可消耗3kW連續制動功率,共計18kW。(3kWarecontinuouslypermissibleperresistor.Thiscorrespondstoatotalof18kW.)結論(Conclusion)此例中,需4臺9352制動斬波器,每臺9352需配備6支各18的電阻組成的電阻橋做為制動電阻。(Atotalof4brakingchoppers9352areneeded.Eachchopperreceivesaresistornetworkwithsi*18resistors.)傳動軸(Spindle)計算轉動慣量Calculationofthemomentofinertia一局部轉動慣量產生于傳動軸的幾何形狀:(Momentofinertiaarisingfromthegeometryofthespindle)傳動軸用于圓柱體傳動時:(Forasolidcylinderapplies) (STYLEREF1\n4.SEQGleichung\*ARABIC\n23)該固體為鋼質時:(Forsteelapplies) (STYLEREF1\n4.SEQGleichung\*ARABIC\n24)另一局部轉動慣量產生于負載質量及傳動軸與其軸閂之間的摩擦:(Momentofinertiaarisingfromthemassoftheloadandthespindleboltwithreferencetothespindle) (STYLEREF1\n4.SEQGleichung\*ARABIC\n25) (STYLEREF1\n4.SEQGleichung\*ARABIC\n26)總轉軸慣量為:(Asaresult,thetotalmomentofinertiaisasfollows) (STYLEREF1\n4.SEQGleichung\*ARABIC\n27) (STYLEREF1\n4.SEQGleichung\*ARABIC\n28)運動學分析:(Kinematics)本例中的速度曲線如下列圖所示,由于該曲線在往復過程中是一致的,故在此僅對前向運動中的數據進展計算。(Thediagramshowsthespeedprofileoftheapplication.Sincetheprofileisthesameforforwardandbackwarddriving,itissufficienttoe*amineforwarddrivingonly.)求加速及延遲時間:(Calculationofaccelerationanddelay) (STYLEREF1\n4.SEQGleichung\*ARABIC\n29)隱藏距離:(Distancecovered) (STYLEREF1\n4.SEQGleichung\*ARABIC\n30)這說明在恒定傳動中存在0.18m的隱藏距離,傳動速度為12m/min時,這段距離需用0.9s。(Thismeansthat0.18mhavetobecoveredduringconstantdriving.Incaseof12m/min.,thistakes0.9s.) (STYLEREF1\n4.SEQGleichung\*ARABIC\n31)圖中各段時間為:t1=0.3st2=0.9s t3=0.3s t4=0.1s T=1.6s。(Theindividualtimesare:t1=0.3s t2=0.9s t3=0.3s t4=0.1s T=1.6s.)線速度與角速度的轉換為:(Thetranslatoryvariablesaretransferredtotherotatoryvariablesasfollows) (STYLEREF1\n4.SEQGleichung\*ARABIC\n32) (STYLEREF1\n4.SEQGleichung\*ARABIC\n33)因而,角速度為:(Asaresult,theangularvelocityisasfollows) (STYLEREF1\n4.SEQGleichung\*ARABIC\n34)又因為該角速度對應轉速為n=1200rev/min。(Thiscorrespondstoaspeedofn=1200rev./min)因此,該角速度為:(Asaresult,theangularvelocityisasfollows:) (STYLEREF1\n4.SEQGleichung\*ARABIC\n35)動態傳遞轉矩如下式計算:(Thedynamicprocesstorqueiscalculatedasfollows) (STYLEREF1\n4.SEQGleichung\*ARABIC\n36)首先,靜態轉矩為:(Determinationofthestationarytorque) (STYLEREF1\n4.SEQGleichung\*ARABIC\n37) (STYLEREF1\n4.SEQGleichung\*ARABIC\n38)制過過程中,靜態轉矩可用下式求出:(Duringthebraking,thefollowingappliestothestationarytorque) (STYLEREF1\n4.SEQGleichung\*ARABIC\n39)傳動軸成效可按下式計算:(Thespindleefficiencyiscalculatedasfollows) (STYLEREF1\n4.SEQGleichung\*ARABIC\n40) ith (STYLEREF1\n4.SEQGleichung\*ARABIC\n41)摩擦系數取決于傳動軸的類型(Lenzeformulacollection,s=0.01)。[Thefrictioncoefficientofthespindleresultsfromthespindletype(Lenzeformulacollection,s=0.01).]總傳遞扭矩為動態轉矩與靜態轉矩之和。(Thetotalprocesstorquecanbefoundbyaddingthedynamicandthestationaryponents.) (STYLEREF1\n4.SEQGleichung\*ARABIC\n42)其對應的功率為:(Thecorrespondingprocesspower) (STYLEREF1\n4.SEQGleichung\*ARABIC\n43)總傳遞轉矩的計算值如下所示:(Thecalculatedvaluesforthetotaltorquearelistedbelow)時間(Period)t[s]轉矩(Torque)Mtotal[Nm]t1=0.3M1=2.28t2=0.9M2=0.51t3=0.3M3=-1.34t4=0.1M4=0有效轉矩取決于所選電機。(Theeffectivetorqueisrelevantforselectingamotor.) (STYLEREF1\n4.SEQGleichung\*ARABIC\n44)根據上表中數據:T=1.6s;Meff=1.21Nm。(IfthevaluesshowninthetableareusedwithT=1.6s:Meff=1.21Nm.)所選電機為:(Selectionofthemotor)電源電壓230V,角型連接的MDFMA71-12電機。理由:其額定轉矩大于本例中所需之有效轉矩,額定轉速明顯大于本例中所需傳遞速度。(MDFMA71-12becausetheratedtorqueishigherthantheeffectivetorqueoftheapplication.Theratedspeedisslightlyhigherthantherequestedprocessspeed.Themotorisdelta-connectedwith230V.)電機型號(Motortype)軸高〔A*is〕額定轉速(Speed)額定轉矩(Torque)額定功率(Power)額定電流(Current)電源電壓(Connection)額定頻率(Frequency)heightVoltagehnrMrPrIV(mm)(min-1)(Nm)(kW)(A)(V)(Hz)MD*MA71-127113551.80.250.85/1.5400/23050電機型號(Motortype)功率因子(Power)成效(Efficiency)堵轉轉矩〔StallTorque〕緊轉矩〔TighteningTorque〕啟始電流〔StartingCurrent〕轉動慣量(Momentofinertia)重量(Weight)factorMrMAIA/IrJMcos(Nm)(Nm)(kgm2)(kg)MD*MA71-120.700.613.43.43.80.00065.9校核電機負載能力Checkofmotorloadcapacity:由于電機轉矩,會產生較高的動態應力。(Owingtothetorqueofthemotor,thedynamicstresswillbehigher.) (STYLEREF1\n4.SEQGleichung\*ARABIC\n45) (STYLEREF1\n4.SEQGleichung\*ARABIC\n46)因此,可按下式求出新的動態轉矩:(Thenewdynamicprocesstorqueisasfollows) (STYLEREF1\n4.SEQGleichung\*ARABIC\n47) (STYLEREF1\n4.SEQGleichung\*ARABIC\n48)因而,總轉矩如下表所示:(Asaresult,thetotaltorqueisasfollows)時間(Period)t[s]轉矩(Torque)Mtotal[Nm]t1=0.3M1=2.53t2=0.9M2=0.51t3=0.3M3=-1.59t4=0.1M4=0有效轉矩為:(Theeffectivetorqueisasfollows) Meff=1.35Nm在計算電流值時,應進一步校核負載能力。(Loadcapacitycanandshouldbee*aminedmoredetailedwhencalculatingthecurrent.)此時,應根據轉矩曲線求電流曲線。(Inthiscase,thecurrentprofileiscalculatedfromthetorqueprofile.)電流Ia,r及If,r得自額定數據。(ThecurrentsIa,randIf,rresultfromtherateddata) (STYLEREF1\n4.SEQGleichung\*ARABIC\n49) (STYLEREF1\n4.SEQGleichung\*ARABIC\n50)根據下表的等式,可由轉矩求出有效電流。(Owingtothefollowinggeneralrelation,thecorrespondingeffectivecurrentcanbecalculatedfromthetorqueM.) (STYLEREF1\n4.SEQGleichung\*ARABIC\n51)總電流為:(Thetotalcurrentcanbeca
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯系上傳者。文件的所有權益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網頁內容里面會有圖紙預覽,若沒有圖紙預覽就沒有圖紙。
- 4. 未經權益所有人同意不得將文件中的內容挪作商業或盈利用途。
- 5. 人人文庫網僅提供信息存儲空間,僅對用戶上傳內容的表現方式做保護處理,對用戶上傳分享的文檔內容本身不做任何修改或編輯,并不能對任何下載內容負責。
- 6. 下載文件中如有侵權或不適當內容,請與我們聯系,我們立即糾正。
- 7. 本站不保證下載資源的準確性、安全性和完整性, 同時也不承擔用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。
最新文檔
- 2025關于制定個人的汽車租賃合同范本
- 2025北京市家具買賣合同范本(桌椅類)
- 妊娠合并缺鐵性貧血
- 小說家創作藝術與職業發展全解析
- 幼兒園醫學啟蒙教育
- 河北省衡水市2024-2025學年高二下學期4月期中聯考試題 生物 含答案
- 浙江省衢州市五校聯盟2024-2025學年高二下學期期中聯考語文試卷(PDF版含答案)
- 委托勘察業務協議
- 某酒吧的廣告策劃
- 某房地產販賣技巧培訓
- 麥收消防安全培訓課件
- 2025展覽館裝飾工程合同范本
- 《科普技巧常識》課件
- 2025年中國全電腦橫機市場現狀分析及前景預測報告
- 2019-2025年房地產經紀協理之房地產經紀操作實務過關檢測試卷B卷附答案
- 2025年全國保密教育線上培訓考試試題庫及答案(奪冠)帶答案詳解
- 滬教牛津版(深圳用)英語五年級下冊Unit-11-Chinese-festivals課件
- 初中歷史明清時期的科技與文化 課件 2024-2025學年統編版七年級歷史下冊
- 2025年上半年發展對象題庫(含答案)
- 甘露特鈉膠囊聯合多奈哌齊片治療輕中度阿爾茨海默病的療效及腸道菌群影響
- 大連銀行招聘筆試真題2024
評論
0/150
提交評論