五版題庫試題選編（六章絡合滴定法）1(07030703的酸效應曲線是指) 線pM-pH(C)lgK’(MY)-pH線 (D)lg?Y(H)-pH1分(0703)0703 (D)2(07060706pH 10.0 , ?Zn(NH3)=104.7,?Zn(OH)=102.4,?Y(H)=100.5 lgK’(ZnY)為 ( ) =≥6.0 (D)lg,Pb2+2(0740)10-9.26.3×10-10)10(07460746NH3-NH4Cl,0.10mol,pH=9.0,10-5.62(0761)1.A,2.C,3.B,4.D10(0760)pH=5.5,,2.000×10-2mol/L2.000×10-2mol/LPb2+、Al3+Pb2+,NH4FAl3+,并使終點1.0×10-2mol/L,試終點誤差。知lgK(AlY)=16.3lgK(PbY)=18.0;pH=5.5?Y(H)=105.5,pPbt()=7.6?Al(OH)=100.4?Pb(OH)=1,AlF63-lg?1~lg?6別6.1,11.2,15.0,17.7,19.4,19.710(0760)-2.0+6.1?Al(F)=1+10+10-4.0+11.2+10-6.0+15.0+10-8.0+17.7+10-10.0+19.4+10-12.0+19.7=109.9c(Al) 102.0K(AlY)=1+10-11.9+16.3 =104.4?Y(H)(105.5) ?Y=105.5lgK’(PbY)=18.0-5.5=12.5, =(12.5+2)/2=7.3 100.3-10-0.3-4Et=───────×100%=7×10%12.5-2.01/2(10)10(0752)=105.5

,10(0752)= ?Zn=105.5+102.4=105.5/2 =(16.5-0.5-5.5+2.0)/2=6.3pZn=pZn’+lg?Zn=6.3+5.5=11.810(0755)0.02000Pb2+Ca2+混合Pb2+,5.0。:lgK’(PbY)和= 10-2.0-4.310 pY’pY’5.7-1.34.42(08020802以下 表 述 正 確 的是--------------------------------------------------------------------------------( ) (A)二甲酚橙指示使用二甲酚橙既可適用于酸也適用于弱堿(C)T指示劑只適用(D)T2(0802)0802(D)1(08040804Mg2+,T ,Fe3+致-------------------( ) (A),前(C),(D),1(0804)0804(A)2(0805)T ,,pKa2=6.3 pKa3=11.6H2In- HIn2- In3- 紅 藍橙是) (A) pH (C)pH=6.3~11.6 (D)pH=6.3±1 2(0805) (C)2(0806),≤1?pM=±,M濃干擾N濃1/10,欲控制M,則要求lgK(MY)?lgK(NY)大-----------------------------------------( (A)5 (B)6 (C)7 (D)8 2(0806) (C)1Fe3+,Al3+,Ca2+,Mg2+混,測Fe3+,Al3+含時,了消除Ca2+,Mg2+ 干 擾 , 最 簡 便 方 是---------------------------------------------------------------------------( ) (A)法(B)控制法(C)掩蔽法 (D)萃取11(08190819,是) (A2 (B4 (C6 (D8 1(08190819(C)2(0820): pKa1=1.9 pKa2=12.2H2In+HInIn- 綠 黃 ,,pH__________。2+Ca,,2(0820) 2.0~12.0(+) (+2(0830)0830Ca2+,,(、低或無影) 2(0830)0830無影響10(0841)0841pH=5.5Zn2+,Cd2+Zn2+,以KI掩蔽Cd2+,采二甲酚橙,知lgK(ZnX)=14.5,lgK(CdX)=13.0,pH=5.5:lg?X(H)=4.6、pZn